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Overview

I am a Computer Science Engineer. I have 8 years of IT expwrience and 2 years of teaching experience as tution teacher for grade 6-9.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

JSS Noida 2010

Bachelor of Technology (B.Tech.)

Address

Vinayaka Nagar, Hyderabad, India - 500049

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Teaches

Computer Classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Computer Classes

8

Type of Computer course taken

Training in Computer tools usage, Software Programming, Training in Software application usage, Basics of Computer usage

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics, Computers

ICSE Subjects taught

Physics, Mathematics, Computer Science

Taught in School or College

No

Teaching Experience in detail in Class 6 Tuition

I have taught more than 15 6-10 class students in the last 2 years. I am an IT professional, who also take seminars on Data Analytics. I have some unique models to explain the topics to students. I take home tuitions but, due to the COVID situation, I have discontinued the same. Now I am available online only. I am ready to give 1-week demo classes for interested students.

Reviews

No Reviews yet!

FAQs

1. Which computer courses do you teach?

Training in Computer tools usage, Software Programming, Training in Software application usage and others

2. Which classes do you teach?

I teach Class 6 Tuition and Computer Classes.

3. Do you provide a demo class?

Yes, I provide a free demo class.

4. How many years of experience do you have?

I have been teaching for 8 years.

Answers by Amit Hansani (3)

Answered on 29/05/2020 Learn IT Courses

Since you are from a Recruitment background, you can also find MBA in HR to go for HR management side. Secondly, if you want to follow the technical path, you can get into SAP HCM, also called SAP HR courses. Thirdly, you might get into data analytics, as you have a command on how to gather data on recruiters.... ...more

Since you are from a Recruitment background, you can also find MBA in HR to go for HR management side.

Secondly, if you want to follow the technical path, you can get into SAP HCM, also called SAP HR courses.

Thirdly, you might get into data analytics, as you have a command on how to gather data on recruiters. Still, you should only go towards this path if you are interested in data. Data analytics is not just restricted to HR/recruitment side.

Fourthly, you can enhance your soft skills and make yourself perfect in Powerpoint Presentations as you require to build so many presentations for your recruitment drive( If you are not already an expert in that.)

Answers 188 Comments
Dislike Bookmark

Answered on 29/05/2020 Learn Tuition

5(x^2 + y^2 + z^2) = 4(xy +yz+zx) Break the equation like this: 2((x^2 + y^2 - 2xy) + (x^2 + z^2 - 2xz) + (y^2 + z^2 - 2yz)) + x^2 + y^2 + z^2 = 0 2((x-y)^2 + (x-z)^2 + (y-z)^2) + x^2 + y^2 + z^2 = 0 Since sum of squares are 0 which mean x^2 + y^2 + z^2 is also 0 And since they cannot be negative, and... ...more

5(x^2 + y^2 + z^2)  = 4(xy +yz+zx)

Break the equation like this:

2((x^2 + y^2 - 2xy) + (x^2 + z^2 - 2xz) + (y^2 + z^2 - 2yz)) + x^2 + y^2 + z^2 = 0

2((x-y)^2 + (x-z)^2 + (y-z)^2) + x^2 + y^2 + z^2 = 0

Since sum of squares are 0 which mean x^2 + y^2 + z^2 is also 0

And since they cannot be negative, and there sum is 0 that means there can be only 1 unique solutions x=y=z=0. 

Hence the ratio cannot be determined. as it is 0:0:0. Infact there is no such thing as 0:0:0, hence no ration defined.

Answers 353 Comments
Dislike Bookmark

Teaches

Computer Classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Computer Classes

8

Type of Computer course taken

Training in Computer tools usage, Software Programming, Training in Software application usage, Basics of Computer usage

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics, Computers

ICSE Subjects taught

Physics, Mathematics, Computer Science

Taught in School or College

No

Teaching Experience in detail in Class 6 Tuition

I have taught more than 15 6-10 class students in the last 2 years. I am an IT professional, who also take seminars on Data Analytics. I have some unique models to explain the topics to students. I take home tuitions but, due to the COVID situation, I have discontinued the same. Now I am available online only. I am ready to give 1-week demo classes for interested students.

No Reviews yet!

Answers by Amit Hansani (3)

Answered on 29/05/2020 Learn IT Courses

Since you are from a Recruitment background, you can also find MBA in HR to go for HR management side. Secondly, if you want to follow the technical path, you can get into SAP HCM, also called SAP HR courses. Thirdly, you might get into data analytics, as you have a command on how to gather data on recruiters.... ...more

Since you are from a Recruitment background, you can also find MBA in HR to go for HR management side.

Secondly, if you want to follow the technical path, you can get into SAP HCM, also called SAP HR courses.

Thirdly, you might get into data analytics, as you have a command on how to gather data on recruiters. Still, you should only go towards this path if you are interested in data. Data analytics is not just restricted to HR/recruitment side.

Fourthly, you can enhance your soft skills and make yourself perfect in Powerpoint Presentations as you require to build so many presentations for your recruitment drive( If you are not already an expert in that.)

Answers 188 Comments
Dislike Bookmark

Answered on 29/05/2020 Learn Tuition

5(x^2 + y^2 + z^2) = 4(xy +yz+zx) Break the equation like this: 2((x^2 + y^2 - 2xy) + (x^2 + z^2 - 2xz) + (y^2 + z^2 - 2yz)) + x^2 + y^2 + z^2 = 0 2((x-y)^2 + (x-z)^2 + (y-z)^2) + x^2 + y^2 + z^2 = 0 Since sum of squares are 0 which mean x^2 + y^2 + z^2 is also 0 And since they cannot be negative, and... ...more

5(x^2 + y^2 + z^2)  = 4(xy +yz+zx)

Break the equation like this:

2((x^2 + y^2 - 2xy) + (x^2 + z^2 - 2xz) + (y^2 + z^2 - 2yz)) + x^2 + y^2 + z^2 = 0

2((x-y)^2 + (x-z)^2 + (y-z)^2) + x^2 + y^2 + z^2 = 0

Since sum of squares are 0 which mean x^2 + y^2 + z^2 is also 0

And since they cannot be negative, and there sum is 0 that means there can be only 1 unique solutions x=y=z=0. 

Hence the ratio cannot be determined. as it is 0:0:0. Infact there is no such thing as 0:0:0, hence no ration defined.

Answers 353 Comments
Dislike Bookmark

Amit Hansani conducts classes in Class 6 Tuition and Computer. Amit is located in Vinayaka Nagar, Hyderabad. Amit takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 8 years of teaching experience . Amit has completed Bachelor of Technology (B.Tech.) from JSS Noida in 2010. HeĀ is well versed in Hindi and English.

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