https://www.urbanpro.com/hapur/swati-r/17015013 # Swati R.

## NET JRF qualified and preparing for PhD..

## Overview

## Languages Spoken

## Education

## Address

## Verified Info

## Teaches

## Reviews

## FAQs

## Lessons (1)

## Answers by Swati R. (4)

## Teaches

Research Aptitude, Communication, Teaching Aptitude, Data Interpretation, Logical Reasoning, Reading Comprehension

Financial Management, Human Resource Management, Management Accounting, Business Mathematics and Statistics, Micro & Macro Economics, Financial Accounting, Company Law, Corporate Accounting

## Answers by Swati R. (4)

Answered on 03/01/2022 Learn CBSE/Class 10/Mathematics/UNIT VII: Statistics and probability/Statistics

Answered on 03/01/2022 Learn CBSE/Class 10/Mathematics/UNIT VII: Statistics and probability/Statistics

in this question mean is already given and we know that:- mean = sum of total numbers / total number of observations 15 = 2+6+7+a / 4 15*4 = 15+a 60 = 15+a 60-15 = a a= 45 now we have found the value of a=45, we will... ...more Answered on 03/01/2022 Learn CBSE/Class 10/Mathematics/UNIT VII: Statistics and probability/Statistics

## Lessons (1)

Methods of measuring Ep: Proportionate Method || Geometric Method || Total Outlay Method

Avas Vikas Colony, Hapur, India - 245101.

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Swati R.✕

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Swati R. describes herself as NET JRF qualified and preparing for PhD... She conducts classes in BCom Tuition, Class 11 Tuition and Class 12 Tuition. Swati is located in Avas Vikas Colony, Hapur. Swati takes Regular Classes- at her Home and Online Classes- via online medium. She has 1 years of teaching experience . Swati has completed Bachelor of Commerce (B.Com.) from Chaudhary Charan Singh university in 2017 and Master of Commerce (M.Com.) from Chaudhary Charan Singh university,meerut in 2019. She is well versed in Hindi and English.

Hindi Mother Tongue (Native)

English Mother Tongue (Native)

Chaudhary Charan Singh university 2017

Bachelor of Commerce (B.Com.)

Chaudhary Charan Singh university, meerut 2019

Master of Commerce (M.Com.)

NTA 2020

JRF

Avas Vikas Colony, Hapur, India - 245101

Education Verified

Phone Verified

Email Verified

Report this Profile

✕

x

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

UGC NET Exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

I am willing to Travel

Tutor's Home

UGC_NET_Paper_I_Subjects

Research Aptitude, Communication, Teaching Aptitude, Data Interpretation, Logical Reasoning, Reading Comprehension

UGC_NET_Papers

Paper I, Paper II / Paper III

Subject

Commerce

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Business Studies, Accountancy, Economics

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Accountancy, Economics

Taught in School or College

No

BCom Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BCom Tuition

1

BCom Subject

Financial Management, Human Resource Management, Management Accounting, Business Mathematics and Statistics, Micro & Macro Economics, Financial Accounting, Company Law, Corporate Accounting

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

No

No Reviews yet!

1. Which classes do you teach?

I teach BCom Tuition, Class 11 Tuition, Class 12 Tuition and UGC NET Exam Coaching Classes.

2. Do you provide a demo class?

No, I don't provide a demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Methods of measuring Ep: Proportionate Method || Geometric Method || Total Outlay Method

https://youtu.be/atUAlLLptlo

Answered on 16/10/2022 Learn Tuition/BCom Tuition

If your basics of class 11th and 12th are not cleared then it is required.

Like 0

Answers 8 Comments Answered on 03/01/2022 Learn CBSE/Class 10/Mathematics/UNIT VII: Statistics and probability/Statistics

in this question mean is already given and we know that:- mean = sum of total numbers / total number of observations 15 = 2+6+7+a / 4 15*4 = 15+a 60 = 15+a 60-15 = a a= 45 now we have found the value of a=45, we will... ...more

in this question mean is already given and we know that:-

mean = sum of total numbers / total number of observations

15 = 2+6+7+a / 4

15*4 = 15+a

60 = 15+a

60-15 = a

a= 45

now we have found the value of a=45, we will put this value in second series:-

mean = sum of all numbers / total number of observations

50 = 6+18+1+45(value of a) + b / 5

50*5 = 70 + b

250 = 70 + b

b = 250 - 70

b = 180

Like 0

Answers 2 Comments Answered on 03/01/2022 Learn CBSE/Class 10/Mathematics/UNIT VII: Statistics and probability/Statistics

in this question mean is already given and we know that:- mean = sum of total numbers / total number of observations 15 = 2+6+7+a / 4 15*4 = 15+a 60 = 15+a 60-15 = a a= 45 now we have found the value of a=45, we will... ...more

in this question mean is already given and we know that:-

mean = sum of total numbers / total number of observations

15 = 2+6+7+a / 4

15*4 = 15+a

60 = 15+a

60-15 = a

a= 45

now we have found the value of a=45, we will put this value in second series:-

mean = sum of all numbers / total number of observations

50 = 6+18+1+45(value of a) + b / 5

50*5 = 70 + b

250 = 70 + b

b = 250 - 70

b = 180

Like 0

Answers 2 Comments Answered on 03/01/2022 Learn CBSE/Class 10/Mathematics/UNIT VII: Statistics and probability/Statistics

First 10 Natural numbers are:- 1,2,3,4,5,6,7,8,9,10 Mean = Sum of all numbers/ total number of observations = 1+2+3+4+5+6+7+8+9+10 / 10 = 55/ 10 = 5.5 Therefore, 5.5 is the mean of first 10 natural numbers ...more

First 10 Natural numbers are:- 1,2,3,4,5,6,7,8,9,10

Mean = Sum of all numbers/ total number of observations

= 1+2+3+4+5+6+7+8+9+10 / 10

= 55/ 10

= 5.5

Therefore, 5.5 is the mean of first 10 natural numbers

Like 0

Answers 1 Comments UGC NET Exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

I am willing to Travel

Tutor's Home

UGC_NET_Paper_I_Subjects

UGC_NET_Papers

Paper I, Paper II / Paper III

Subject

Commerce

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Business Studies, Accountancy, Economics

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE

CBSE Subjects taught

Accountancy, Economics

Taught in School or College

No

BCom Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BCom Tuition

1

BCom Subject

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

No

No Reviews yet!

Answered on 16/10/2022 Learn Tuition/BCom Tuition

If your basics of class 11th and 12th are not cleared then it is required.

Like 0

Answers 8 Comments

in this question mean is already given and we know that:- mean = sum of total numbers / total number of observations 15 = 2+6+7+a / 4 15*4 = 15+a 60 = 15+a 60-15 = a a= 45 now we have found the value of a=45, we will... ...more

in this question mean is already given and we know that:-

mean = sum of total numbers / total number of observations

15 = 2+6+7+a / 4

15*4 = 15+a

60 = 15+a

60-15 = a

a= 45

now we have found the value of a=45, we will put this value in second series:-

mean = sum of all numbers / total number of observations

50 = 6+18+1+45(value of a) + b / 5

50*5 = 70 + b

250 = 70 + b

b = 250 - 70

b = 180

Like 0

Answers 2 Comments

in this question mean is already given and we know that:-

mean = sum of total numbers / total number of observations

15 = 2+6+7+a / 4

15*4 = 15+a

60 = 15+a

60-15 = a

a= 45

now we have found the value of a=45, we will put this value in second series:-

mean = sum of all numbers / total number of observations

50 = 6+18+1+45(value of a) + b / 5

50*5 = 70 + b

250 = 70 + b

b = 250 - 70

b = 180

Like 0

Answers 2 Comments

First 10 Natural numbers are:- 1,2,3,4,5,6,7,8,9,10 Mean = Sum of all numbers/ total number of observations = 1+2+3+4+5+6+7+8+9+10 / 10 = 55/ 10 = 5.5 Therefore, 5.5 is the mean of first 10 natural numbers ...more

First 10 Natural numbers are:- 1,2,3,4,5,6,7,8,9,10

Mean = Sum of all numbers/ total number of observations

= 1+2+3+4+5+6+7+8+9+10 / 10

= 55/ 10

= 5.5

Therefore, 5.5 is the mean of first 10 natural numbers

Like 0

Answers 1 Comments https://youtu.be/atUAlLLptlo

Share this Profile

Reply to 's review

Enter your reply*

Your reply has been successfully submitted.

✕

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.