Zinc liberate the hydrogen with dilute HCl but Copper not?

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Due to its position in electrochemical series . Zinc reacts with hcl to produce hydrogen gas because it's more reactive than copper.
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Cu is less reactive than zinc
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Because zinc is strong reducing agent and copper is strong oxidizing agent with respect to hydrogen.............
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Copper (Cu) does not liberate H2 from dilute sulphuric acid because its reduction potential is higher (+0.34) than that for the reaction (2H++2e??H2?) for which the reduction potential is Zero.
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Zinc liberates H2 gas when it is treated with dilute HCl ie hydrachloric acid because Zinc is more reactive thn hydrogen so it displaces hydrogen from it 's compound ie HCl and forms Zinc choride ie ZnCl2 wheras copper does not react with dilute hydrochloric acid ie HCl because copper is less reactive...
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Zinc liberates H2 gas when it is treated with dilute HCl ie hydrachloric acid because Zinc is more reactive thn hydrogen so it displaces hydrogen from it 's compound ie HCl and forms Zinc choride ie ZnCl2 wheras copper does not react with dilute hydrochloric acid ie HCl because copper is less reactive than hydrogen so it can 't displace hydrogen from it 's compound. read less
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Zinc is oxidised by hydrogen ions, whereas copper is not. Copper ions are stronger oxidising agents than hydrogen ions are, so hydrogen is unable to affect copper metal. Zinc, however, is a fairly powerful reducing agent, and zinc ions are unable to oxidise hydrogen.
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computer science and physics teacher

bcz zinc is more reactive than copper
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Expert of triod (physics , chemsitry and maths )

zn is above in electrochemical series than copper
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Home Tutor with 1 year experience

Copper (Cu) does not liberate H2 from dilute sulphuric acid because its reduction potential is higher than zinc
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It all can be studied using electrochemical series. The element above in electrochemical series can displace lower element from its ioninc compound. Since copper is below hydrogen in electrochemical series, it cannot displace hydrogen from HCl and hence hydrogen is not liberated in this case.
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