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Integration by substitution.

B.Sudhakar
03/01/2017 0 0

Let's solve an example using 'u' substitution method.

∫ sin² x cos x dx ------------------------A

As we can see " cos x " along with " sin x " and we don't have any ready made formula for the product of two functions in integration, let's try to eliminate one of them. As cos x is raised to power one, we can eliminate cos x by using ' u ' substitution.

Let u = sin x,   by differentiating  "u " wrt "x "  du / dx = cos x or  dx = du / cos x

By substituting "u" and "dx" in  "A"

∫ sin² x cos x dx = ∫ u² cos x du / cos x

= ∫ u² cos x / cos x du.               ( cos x cancels out )

∫ u² du

= u³ / 3 + c  

=1/3 sin³ x + c.    (by substituting "sin x" back in place of " u ")

∴ ∫ sin² x cos x dx = 1/3 sin³ x + c

 

 

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