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https://www.urbanpro.com/delhi/vikram-prabhakaran # Vikram Prabhakaran

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## Answers by Vikram Prabhakaran (2)

Reasoning Ability, Quantitative aptitude/ Numerical ability, General awareness/ Financial awareness, Interview prep, Computer aptitude

## Answers by Vikram Prabhakaran (2)

Vikram Prabhakaran

Malviya Nagar, Delhi, India - 110017

Malviya Nagar, Delhi, India - 110017.

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Details verified of Vikram Prabhakaran✕

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I have been taking classes for IBPS, SBI and SSC for past couple of years. In 2015 I myself cleared both IBPS-PO and SBI-PO. If you have a problem clearing these exams I can definitely help you get through.

English

Hindi

Indian Institute of Technology Dhanbad (formerly Indian School of Mines Dhanbad) 2011

Bachelor of Technology (B.Tech.)

Malviya Nagar, Delhi, India - 110017

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MBA Entrance Coaching classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

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No Reviews yet! Be the first one to Review

1. Which classes do you teach?

I teach Bank Clerical Exam Coaching, IBPS Exam Coaching, MBA Entrance Coaching and Staff Selection Commission Exam Classes.

2. Do you provide a demo class?

No, I don't provide a demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Answered on 02/12/2016 Exam Coaching/IBPS Exam Coaching

I can understand that starting a habit of reading a newspaper is little difficult so I will not ask you to do so right away. This is only for getting you highest possible marks in IBPS English section in a limited period of time. Practice Grammar, Vocabulary and Comprehension from "Objective General... ...more

I can understand that starting a habit of reading a newspaper is little difficult so I will not ask you to do so right away. This is only for getting you highest possible marks in IBPS English section in a limited period of time. Practice Grammar, Vocabulary and Comprehension from "Objective General English" by R.S.Aggarwal. If you get stuck with grammar basics then refer "British English Grammar" by Ashok Kumar Singh.

Like 0

Answers 18 Comments Answered on 02/12/2016 Exam Coaching/MBA Entrance Coaching/CAT Coaching

It needs to be visualized first that there can be only 1 odd number between any two even numbers and vice versa because if you place 3 odd numbers between 2 even numbers then some pair of even numbers will not have any odd numbers between them lets assume a set of numbers 1, 2, 3, 4,... ...more

It needs to be visualized first that there can be only 1 odd number between any two even numbers and vice versa because if you place 3 odd numbers between 2 even numbers then some pair of even numbers will not have any odd numbers between them lets assume a set of numbers 1, 2, 3, 4, 5, 6 2, 1 ,3 ,5 ,4 ,6 not satisfying the condition thus we have only 2 of types possibility that satisfies the given condition: 1 2 3 4 5 6 2 1 4 3 6 5 the two types of possibility happened because the number of odd and number of even numbers are same but for a set of odd numbers there will be only one type of possibility i.e. starting with odd numbers. e.g.:- 2 3 4 5 1 not satisfying the condition 1 2 3 4 5 Now coming to the question. Lets suppose, n is even and thus n=2t+2 (where t is an integar with t>0) thus t+1 even numbers and t+1 odd numbers 2*(t+1)! (t+1)! = 72 (t+1)! = 6 t=2 n=6. Lets suppose n is odd and thus n=2t+1 (where t is an integar with t>0) thus t even numbers and t+1 odd numbers (2t+1)! (t)! = 72 for t=1 rhs =6 for t=2 rhs =240 thus the above equation will not be satisfied for any value of t. Hence, n = 6

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Answers 3 Comments MBA Entrance Coaching classes 3.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Bank Clerical Exam Coaching classes 3.5

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Bank Clerical Exam Coaching classes

3

Target section catered to

Reasoning Ability, Quantitative aptitude/ Numerical ability, General awareness/ Financial awareness, Interview prep, Computer aptitude

IBPS Exam Coaching 3.5

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in IBPS Exam Coaching

3

Target section catered to

Staff Selection Commission Exam Coaching 3.5

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Staff Selection Commission Exam Coaching

2

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No Reviews yet! Be the first one to Review

Answered on 02/12/2016 Exam Coaching/IBPS Exam Coaching

I can understand that starting a habit of reading a newspaper is little difficult so I will not ask you to do so right away. This is only for getting you highest possible marks in IBPS English section in a limited period of time. Practice Grammar, Vocabulary and Comprehension from "Objective General... ...more

I can understand that starting a habit of reading a newspaper is little difficult so I will not ask you to do so right away. This is only for getting you highest possible marks in IBPS English section in a limited period of time. Practice Grammar, Vocabulary and Comprehension from "Objective General English" by R.S.Aggarwal. If you get stuck with grammar basics then refer "British English Grammar" by Ashok Kumar Singh.

Like 0

Answers 18 Comments Answered on 02/12/2016 Exam Coaching/MBA Entrance Coaching/CAT Coaching

It needs to be visualized first that there can be only 1 odd number between any two even numbers and vice versa because if you place 3 odd numbers between 2 even numbers then some pair of even numbers will not have any odd numbers between them lets assume a set of numbers 1, 2, 3, 4,... ...more

It needs to be visualized first that there can be only 1 odd number between any two even numbers and vice versa because if you place 3 odd numbers between 2 even numbers then some pair of even numbers will not have any odd numbers between them lets assume a set of numbers 1, 2, 3, 4, 5, 6 2, 1 ,3 ,5 ,4 ,6 not satisfying the condition thus we have only 2 of types possibility that satisfies the given condition: 1 2 3 4 5 6 2 1 4 3 6 5 the two types of possibility happened because the number of odd and number of even numbers are same but for a set of odd numbers there will be only one type of possibility i.e. starting with odd numbers. e.g.:- 2 3 4 5 1 not satisfying the condition 1 2 3 4 5 Now coming to the question. Lets suppose, n is even and thus n=2t+2 (where t is an integar with t>0) thus t+1 even numbers and t+1 odd numbers 2*(t+1)! (t+1)! = 72 (t+1)! = 6 t=2 n=6. Lets suppose n is odd and thus n=2t+1 (where t is an integar with t>0) thus t even numbers and t+1 odd numbers (2t+1)! (t)! = 72 for t=1 rhs =6 for t=2 rhs =240 thus the above equation will not be satisfied for any value of t. Hence, n = 6

Like 0

Answers 3 Comments Share this Profile

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