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Surendra Kumar Saini

Rohini, Delhi, India - 110042

Surendra Kumar Saini Class 6 Tuition trainer in Delhi

Surendra Kumar Saini

maths n science

Rohini, Delhi, India - 110042.

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Surendra Kumar Saini describes himself as maths n science. He conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Surendra Kumar is located in Rohini, Delhi. Surendra Kumar takes at students Home and Regular Classes- at his Home. He has 20 years of teaching experience . Surendra Kumar has completed Bachelor of Science (B.Sc.) from Delhi University in 1972. He is well versed in Hindi and English.

Languages Spoken

Hindi

English

Education

Delhi University 1972

Bachelor of Science (B.Sc.)

Address

Rohini, Delhi, India - 110042

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Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

20

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Reviews

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FAQs

1. Which school boards of Class 8 do you teach for?

CBSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 20 years.

Answers by Surendra Kumar Saini (11)

Answered on 01/10/2019 CBSE/Class 9/Mathematics/Unit 5-Mensuration/Heron's formula/NCERT Solutions/Exercise 12.2

S semiperimeter=(35+28+9)2=<36 area of one tile =√36(36_35)(36_28)(36_9)= 6*1* 14.7 = 88.2 square cm approximately. Area of 16 such tiles = 88.2*16= 1411.2sq.cm cost of polishing is 1411.2*1/2 = 705.60
Answers 6 Comments
Dislike Bookmark

Answered on 28/09/2019 CBSE/Class 10/Mathematics

5
Answers 16 Comments
Dislike Bookmark

Answered on 28/09/2019 CBSE/Class 10/Mathematics

3
Answers 16 Comments
Dislike Bookmark

Answered on 28/09/2019 CBSE/Class 10/Mathematics

(x_h)2+(y_k)2=R2 .where H and k are co ordinate s of centre and R is radius of the circle
Answers 21 Comments
Dislike Bookmark

Answered on 28/09/2019 CBSE/Class 10/Mathematics

(Xsquare_Hsquare) +(Ysquare_Ksquare) =Rsquare where H n K are centre and R is radius
Answers 21 Comments
Dislike Bookmark
Class 6 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

20

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 7 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

20

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 8 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

20

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 9 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

20

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

No

Class 10 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

20

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

No

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Answers by Surendra Kumar Saini (11)

Answered on 01/10/2019 CBSE/Class 9/Mathematics/Unit 5-Mensuration/Heron's formula/NCERT Solutions/Exercise 12.2

S semiperimeter=(35+28+9)2=<36 area of one tile =√36(36_35)(36_28)(36_9)= 6*1* 14.7 = 88.2 square cm approximately. Area of 16 such tiles = 88.2*16= 1411.2sq.cm cost of polishing is 1411.2*1/2 = 705.60
Answers 6 Comments
Dislike Bookmark

Answered on 28/09/2019 CBSE/Class 10/Mathematics

5
Answers 16 Comments
Dislike Bookmark

Answered on 28/09/2019 CBSE/Class 10/Mathematics

3
Answers 16 Comments
Dislike Bookmark

Answered on 28/09/2019 CBSE/Class 10/Mathematics

(x_h)2+(y_k)2=R2 .where H and k are co ordinate s of centre and R is radius of the circle
Answers 21 Comments
Dislike Bookmark

Answered on 28/09/2019 CBSE/Class 10/Mathematics

(Xsquare_Hsquare) +(Ysquare_Ksquare) =Rsquare where H n K are centre and R is radius
Answers 21 Comments
Dislike Bookmark

Contact

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Surendra Kumar Saini describes himself as maths n science. He conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Surendra Kumar is located in Rohini, Delhi. Surendra Kumar takes at students Home and Regular Classes- at his Home. He has 20 years of teaching experience . Surendra Kumar has completed Bachelor of Science (B.Sc.) from Delhi University in 1972. He is well versed in Hindi and English.

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