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What's the equation of a circle?

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CBSE/Class 10/Mathematics

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(x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r".
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Well Qualified and Certified Mathematics B.Ed(M.G Usty)Teacher with more than13 years of Experience

(x-h)2+ (y - k) 2 = r2, where (h, k) is the coordinates of the centre of the circle and 'r', the length of the radius of the circle.
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The eq .of circle in standard form is ..x 2+ y2 - 2hx - 2yk + h2 + k2 + c = 0 ..general form if eq.of circle , and derived form of eq. of circle with coordinate x, y, and C = r2 is given as ( x- h) 2 + ( y- k )2 = r2 ...eq. (2)..where h,k are coordinates from centre , radius = r2 ., is derived form circle... read more

The eq .of circle in standard form is ..x 2+ y2 - 2hx - 2yk + h2 + k2 + c = 0 ..general form if eq.of circle , and derived form of eq. of circle with coordinate x, y, and C = r2 is given as ( x- h) 2 + ( y- k )2 = r2 ...eq. (2)..where h,k are coordinates from centre , radius = r2 ., is derived form circle equation ., which can be found once we r given coordinates , r2 value of the circle.

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Math Simply Means My Analysis through Histogram

(X-h) ²+(Y-K) ²=r²..... Where h, k are the Co ordinates of the center r is the radious
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Experienced and versatile instructor for education from Hyderabad india

(X-h) ²+(Y-K) ²=r²..... Where h, k are the Co ordinates of the center r is the radious
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Experienced and versatile instructor for education from Hyderabad india

(X-h) ²+(Y-K) ²=r²..... Where h, k are the Co ordinates of the center r is the radious
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Total teaching experiences is 26 year's of 11 and 12

(x-h)2+(y-k)2=r
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Contact me at 6375 746627 for better conversation. Specialist for Civil Engineering and Upto 10th.

The general form : x2 + y2 + Dx + Ey + F = 0, where D, E, F are constants. If the equation of a circle is in the standard form, we can easily identify the center of the circle, (h, k), and the radius, r . read more

The general form : x2 + y2 + Dx + Ey + F = 0, where D, E, F are constants. If the equation of a circle is in the standard form, we can easily identify the center of the circle, (h, k), and the radius, r .

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(x-g)^2+(y-f)^2=(r)^2 where, (-g,-f) is the centre of the circle
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