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Sandeep Prasad

Laxmisagar, Darbhanga, India - 846009

Sandeep Prasad Class 10 trainer in Darbhanga

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Sandeep Prasad

Tutor

Laxmisagar, Darbhanga, India - 846009.

10 Students taught

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Details verified of Sandeep Prasad

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Education

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Overview

I am an experienced, qualified teacher and tutor with over 5 years of experience in teaching Maths, Physics and Chemistry upto 10th & Maths upto 12th across different boards including CBSE, ICSE, IGCSE State Board and mathematics olympiad. Passionate about solving mathematical problems and chemical equations, over the years I have helped no. of students overcome their fear of Maths, Chemistry & Physics.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Maithili Proficient

Education

LNMU Pursuing

Master of Science (M.Sc.)

Lnmu 2018

Bachelor of Science (B.Sc.)

Address

Laxmisagar, Darbhanga, India - 846009

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Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

IGCSE, ICSE, CBSE, International Baccalaureate, State

IB Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Chemistry, Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

Reviews (6)

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5 out of 5 6 reviews

Sandeep Prasad https://s3-ap-southeast-1.amazonaws.com/tv-prod/member/photo/4265549-small.jpg Laxmisagar
5.0056
Sandeep Prasad
A

"Very good interactive class, focus on deep understanding of concepts and ample time to practice on every concept and one on one doubts are taken regularly."

Sandeep Prasad
A

"Very good interactive class, focus on deep understanding of concepts and ample time to practice on every concept and one on one doubts are taken regularly. "

Sandeep Prasad
R

"To have such a tutor is a good luck. I've attended his classes and till today, I attend it. He understands the problems and circumstances of students. He has a deep knowledge of various topics. His teaching methods are incredible and his way of teaching is very charming. I have never got more than 40 marks in my school exams. But, now I am scoring more than 65 and even 70 out of 80. If you wanna to excel yourself, must contact with Him. Indeed he is an excellent tutor. "

Reply by Sandeep

Thanks! Keshvi for your feedback. All the very best for your JEE preparation!

Sandeep Prasad
S

"He teach students with interest and relate examples with real life experience help them to learn subjects easily with proper understanding. Motivate them to study enjoy learning. Regularly revise learning. Help students with homework assignments engage them with different learning techniques skills and make them feel the subject and topic. "

Have you attended any class with Sandeep? Write a Review

FAQs

1. Which school boards of Class 10 do you teach for?

IGCSE, ICSE, CBSE and others

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach BA Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Math Olympiad Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 3 years.

Answers by Sandeep (2)

Answered on 01 Jun CBSE/Class 10/Science Tuition

The bond formed by the sharing of the electron is called a covalent bond. configuration of is(k-2, L-4). In this configuration, we can see its valence electron is 4; therefore, it cannot lose or gain an electron to fulfil its octet. Then we say that Carbon is a tetravalent and covalent element. That's... ...more

The bond formed by the sharing of the electron is called a covalent bond. configuration of is(k-2, L-4). In this configuration, we can see its valence electron is 4; therefore, it cannot lose or gain an electron to fulfil its octet. Then we say that Carbon is a tetravalent and covalent element. That's why carbon shares the electron with other elements to form a compound. 

Answers 723 Comments
Dislike Bookmark

Answered on 17/10/2019 Tuition

Put x=1&y=-2 in the equation 2(1)-3(-2)=2+6=8 Hence (1,-2) is a solution of 2x-3y=8
Answers 292 Comments
Dislike Bookmark
Class 10 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

IGCSE, ICSE, CBSE, International Baccalaureate, State

IB Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Chemistry, Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

Class 9 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

3

Board

IGCSE, ICSE, CBSE, International Baccalaureate, State

IB Subjects taught

Mathematics, Physics, Chemistry

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Chemistry, Physics, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Class 11 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

1

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 12 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 6 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

3

Board

ICSE, International Baccalaureate, IGCSE, State, CBSE

IB Subjects taught

Mathematics, Science

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

Class 7 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

3

Board

ICSE, International Baccalaureate, IGCSE, State, CBSE

IB Subjects taught

Mathematics, Science

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

Class 8 Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

3

Board

ICSE, International Baccalaureate, IGCSE, State, CBSE

IB Subjects taught

Mathematics, Science

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

BA Tuition 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BA Tuition

3

Field tutored for

Mathematics

BA Mathematics Subjects

Mechanics

Type of class

Crash Course, Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

Math Olympiad classes 5.0

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Math Olympiad classes

3

Answers by Sandeep Prasad (2)

Answered on 01 Jun CBSE/Class 10/Science Tuition

The bond formed by the sharing of the electron is called a covalent bond. configuration of is(k-2, L-4). In this configuration, we can see its valence electron is 4; therefore, it cannot lose or gain an electron to fulfil its octet. Then we say that Carbon is a tetravalent and covalent element. That's... ...more

The bond formed by the sharing of the electron is called a covalent bond. configuration of is(k-2, L-4). In this configuration, we can see its valence electron is 4; therefore, it cannot lose or gain an electron to fulfil its octet. Then we say that Carbon is a tetravalent and covalent element. That's why carbon shares the electron with other elements to form a compound. 

Answers 723 Comments
Dislike Bookmark

Answered on 17/10/2019 Tuition

Put x=1&y=-2 in the equation 2(1)-3(-2)=2+6=8 Hence (1,-2) is a solution of 2x-3y=8
Answers 292 Comments
Dislike Bookmark

Sandeep Prasad describes himself as Tutor. He conducts classes in BA Tuition, Class 10 Tuition and Class 11 Tuition. Sandeep is located in Laxmisagar, Darbhanga. Sandeep takes at students Home and Regular Classes- at his Home. He has 3 years of teaching experience . Sandeep is pursuing Master of Science (M.Sc.) from LNMU. Sandeep has completed Bachelor of Science (B.Sc.) from Lnmu in 2018. HeĀ is well versed in Hindi, English and Maithili. Sandeep has got 6 reviews till now with 100% positive feedback.

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