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Class 12 Tuition > Learn Class XI-XII Tuition (PUC) > What is the equation of tangent and its slope form?
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What is the equation of tangent and its slope form?

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JU-IITKGP & 10+ years experienced for boards, JEE,NEET,OLYMPIAD & 5-12

m= the slope of the tangent= dy/dx Tangent A: y= mx + square root( square of (am) + square of b), where m=the slope of the tangent=dy/dx or at (x1, y1), xx1/square of a + yy1/square of b=1. c = sqrt (a*a*m*m + b*b).
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Trainer

y-y1= m(x-x1)
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Trainer

Slope form y=mx+c
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Mathematics is not about numbers, equation, computation, or algorithms it is about UNDERISTANDING.

General equation of tangent of any curve at point (x1,y1) is (y-y1)=(dy/dx)(x1,y1)(x-x1) where (dy/dx )(x1,y1) is the slope of tangent.
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Maths

Y= mx + c
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Assistant Professor

c = sqrt (a*a*m*m + b*b).
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Tutor

https://www.math.brown.edu/utra/tangentline.html
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An Experienced Trainer

m= the slope of the tangent= dy/dx Tangent A: y= mx + square root( square of (am) + square of b), where m=the slope of the tangent=dy/dx or at (x1, y1), xx1/square of a + yy1/square of b=1.
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