The amount of heat required to raise the temperature of 2.0 x 108kg of water from 0°C to 100°C is equal to __________. (9 x 1013J, 9 x 1012J, 9 x 1011J, 9 x 1010J)

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Ankita M

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Q=mc?T, where Q= amount oh heat required to raise the temperature by ?T c- specific heat capacity of the substance ?T- Temperature difference m-mass of the substance So, Q=2 x (10^8) x 4200 x (100-0) =2 x (10^8) x 4200 x 100 =8400 x (10^8) x...
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Q=mc?T, where Q= amount oh heat required to raise the temperature by ?T c- specific heat capacity of the substance ?T- Temperature difference m-mass of the substance So, Q=2 x (10^8) x 4200 x (100-0) =2 x (10^8) x 4200 x 100 =8400 x (10^8) x 100 =84 x (10^2) x (10^8) x (10^2) =84 x (10^12) =8.4 x (10^13) ?9 x (10^13) J where ? means approximately equal to. It's very important to note that the specific heat capacity of water is 4.18 J/g K, but we need to convert it to SI units to get the right answer. All the units should be same. And so it's equal to 4180 J/kg K ? 4200 J/kg K. Therefore, the right answer is option A. read less
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Tutor

Assuming initial quantity given has a typo and it actually is 2 * 10^8kg The amount of heat required = 8.364 * 10^13J
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Headstart to assured 95+ score in math

B
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Physics Tutor

You must specify the value of Pressure as specific heat varies with pressure. Though for atmospheric pressure 8.36 * 10^13 holds true.
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first option (9*1013 J)
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Q=ms?t is the formula.. ie.,Q=2×10`8×1×100=2×10'10 is the correct answer
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Physics

9 x 1013J
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