UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕

Take Class 12 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Book a Free Demo

Class 12 Tuition > Learn Class XI-XII Tuition (PUC) > 2 and 3
✕

Search in

2 and 3

Asked by Last Modified  

14 Answers

Learn Class XI-XII Tuition (PUC) +1

Follow 0
Answer

Please enter your answer

Physics Teacher

find the attached solution
Comments
Dislike Bookmark

+ or -
Comments
Dislike Bookmark

Educator with26+yrs of international exp.Teaching-Math,Science,Engg,Medical,EntranceExams

Dear Archit, you must have your basics right about the conics section, here particularly, Hyperbola. Suggestions: Try reading basics (Even though you know), then solve some ques based on it and then take on the particular questions. Devote time separately to such topics. I m sure your will over come...
read more
Dear Archit, you must have your basics right about the conics section, here particularly, Hyperbola. Suggestions: Try reading basics (Even though you know), then solve some ques based on it and then take on the particular questions. Devote time separately to such topics. I m sure your will over come by following the said pattern. Come back if you need more help. read less
Comments
Dislike Bookmark

IIT JEE Coach

Hello Archit, Please see the solutions below: 2. Let (h,k) be the midpoint of the chord. Then the equation of the chord with midpoint (h,k) is: (hx/3)-(ky/7) = (h^2/3) - (k^2/7) (Equation given by T1 = S1). 7x + y = 20 is the equation of the same line. Comparing the coefficients of the line...
read more
Hello Archit, Please see the solutions below: 2. Let (h,k) be the midpoint of the chord. Then the equation of the chord with midpoint (h,k) is: (hx/3)-(ky/7) = (h^2/3) - (k^2/7) (Equation given by T1 = S1). 7x + y = 20 is the equation of the same line. Comparing the coefficients of the line we get: h/(3*7) = -k/(7) = ((h^2/3) - (k^2/7))/20 So k/h = -1/3 Now the line whose equation we require to find passes through the origin and (h,k) So the equation of the line is y = (k/h).x Since k/h = -1/3, the equation of the line is y = (-1/3)x ---------------------------------------------------------------------------------------------------------------------------------------------- 3. The equation of the hyperbola can be written as (x^2/16) - (y^2/25) = 1 Let the point on the Hyperbola be (4secA, 5 tan A) The equations of the assymptotes are given by (x^2/16) - (y^2/25) = 0 Factorizing out the 2 stratight lines, we get the 2 equations as y = 5x/4 and y = -5x/4 Let Q be the point on y = 5x/4. Since the abscissa remains same, the x coordinate of Q is 4secA. So the y coordinate of Q is y = 5.4secA/4 = 5secA So Q: (4secA, 5secA). Now R lies on y = -5x/4. Solving similarly like we did for Q, the coordinates of R would be (4secA, -5secA). We also have P: (4secA,5tanA) So, PQ = 5(secA-tanA) and PR = 5(secA+tanA) Therefore, PQ.PR = 25.((secA)^2-(tanA)^2) For any angle A, ((secA)^2-(tanA)^2) = 1 Therefore, PQ.PR = 25. Let me know if you have any questions. Thanks read less
Comments
Dislike Bookmark

Computer wizard and mathematics lover

you can contact me
Comments
Dislike Bookmark

Tutor

Its basic.....eqn. of chord of hyperbola - T1=S which is a standard representation of the chord of a hyperbola if x1,y1 r midpoints. from where u can find out slope of the chord in terms of x1and y1. now this chord is also tangent to the 2nd hyperbola .So put x1,y1 in the tangent eqn. and u also know...
read more
Its basic.....eqn. of chord of hyperbola - T1=S which is a standard representation of the chord of a hyperbola if x1,y1 r midpoints. from where u can find out slope of the chord in terms of x1and y1. now this chord is also tangent to the 2nd hyperbola .So put x1,y1 in the tangent eqn. and u also know the slope m which will b required. Thus u get a eqn. which contains x1,y1 as only variables . Thus u can find out its locus. But i suggest u to learn the topic logically before proceeding with this bcoz it was simple if u had complete idea of the thing read less
Comments
Dislike Bookmark

Tutor

(1+?2)/?2
Comments
Dislike Bookmark

Tutor

1/root 2 + 1
Comments
Dislike Bookmark

Mathematics teacher

I can help you to solve these online
Comments
Dislike Bookmark

JEE/Board Maths Tutor

i suggest u to learn the topic logically before proceeding with this bcoz it was simple if u had complete idea of the thing
Comments
Dislike Bookmark

View 12 more Answers

Related Questions

WHAT IS MEANING OF MOMENT OF INERTIA?
Moment of inertia is the mass property of a rigid body that determines the torque needed for a desired angular acceleration about an axis of rotation. Moment of inertia depends on the shape of the body...
Ravi Ranjan
1 0
8
Two long parallel conductors carry 100 A. If the conductors are separated by 20 mm, the force per meter of length of each conductor will be a.) 100 N. b.) 10 N. c.) 1 N. d.) 0.01 N.
Given data: Current I1 and I2 = 100 Amps; Distance = 20 mm = 20 × 10-3 m; Force = ? We know that the force is found by the following expression. Torque developed force fT=M0 *I1 *I2/(2*(Pi)*d)=4*(Pi)*(10)^-7 *(100)^2/2*(pi)*20*(10)^-3=0.1 N
Kumar Upendra Akshay
Is it possible for one hospital to have an income and expenditure account whereas another has a profit and loss account?
It depends on the type of organisation let me illustrate with an example hospitals that are runned by state government or any NGO or trust does not profit motive hence they will prepare Income and expenditure...
Divya
0 0
5
The SI unit of electrical resistance is __________. (Ampere, Volt, Farad, Ohm)
ohm
Narendra Kumar
Why density of Ice is lesser than water?
The main reason why the density of ice is lesser than that of water is because of its crystal structure. Four hydrogen atoms tetrahedrally surround each oxygen atom in the ice. Two of the hydrogen atoms...
Bitu

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Do and Dont's
-Learn By Examples, By relating it to real life things. You will retain it for long. -Dont ever wait for your teachers or tutors for starting something new topics. Make your own pace study before enyone...

Shashank Upadhyay

0 0
0
Easy way to study organic reactions
You know it is always tough that to study organic reaction without a simple mistake. There is no trick way to study them fast. But there is an easy way to remember some of the reactions. Study the various...

Vivek P S

0 0
0
Physical World And Measurement
There are four fundamental forces which govern both macroscopic and microscopic phenomena. There are:(i) Gravitational force (iii) Electromagnetic force(ii) Nuclear force (iv) Weak forceThe relative strengths...
H

Heena K.

0 0
0
Archimede's Principle
Archimedes' principle: principle that states that a body immersed in a fluid is buoyed up by a force equal to the weight of the displaced fluid. The principle applies to both floating and submerged bodies...

Shabeer N.

1 0
0
Worksheet For Alcohols, Phenols And Ethers
Worksheet Alcohols, Phenols And Ethers: 1. Give the structure of 1,2-dimethoxy methane and 2-ethoxy-1,1-dimethylcyclohexane. (1m) 2. Give the name of alkyl halide and sodium alkoxide used to synthesis...

Ameer Khan

0 0
0

Recommended Articles

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Meet Radhe Shyam Burman, an MBA Tutor from...

Radhe Shyam is a highly skilled accounts and finance trainer with 8 years of experience in teaching. Accounting is challenging for many students and that’s where Radhe Shyam’s expertise comes into play. He helps his students not only in understanding the subject but also advises them on how to overcome the fear of accounts...

Read full article >

Meet Swati, a Hindi Tutor from Bangalore

Swati is a renowned Hindi tutor with 7 years of experience in teaching. She conducts classes for various students ranging from class 6- class 12 and also BA students. Having pursued her education at Madras University where she did her Masters in Hindi, Swati knows her way around students. She believes that each student...

Read full article >

Find Class 12 Tuition near you
Class 12 Tuition in Delhi
Class 12 Tuition in Bangalore
Class 12 Tuition in Chennai
Class 12 Tuition in Hyderabad
Class 12 Tuition in Kolkata
Class 12 Tuition in Mumbai
Class 12 Tuition in Lucknow
Class 12 Tuition in Pune
Class 12 Tuition in Gurgaon
Class 12 Tuition in Noida
Online Tuition Class 12

Looking for Class 12 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 12 Tuition Classes?

The best tutors for Class 12 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 12 Tuition with the Best Tutors

The best Tutors for Class 12 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2025 All Rights Reserved