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Stationary point

Sameer Ninawe
17/03/2017 0 0

Find the stationary point for the curve y = x3 – 3x2 + 3x – 3, and its type.

y = x3 – 3x2 + 3x – 3

dy/dx = 3x2 – 6x + 3

= 3(x2 – 2x + 1)

= 3(x – 1)2

dy/dx = 3(x – 1)2  = 0

doubleright x = 1

When x = 1, y = 13 – 3×12 + 3×1 – 3

= 1 – 3 + 3 – 3  =  -2

(1, -2) is a stationary point.

To determine it type, check dy/dx or y’ around x = 1.

x 0 (LHS) 1 2 (RHS)
dy/dx 3(-1)2 = 3 >0 0 3(1)2 = 3 >0
Curve Increasing Stationary Increasing

 

Since the curve is increasing on both sides of (1, -2), the curve is monotonic increasing.
And (1, -2) is a point of horizontal inflection.

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