Integration of sin3x+Cos4x?

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Jagdeep Khandelwal

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-1/3cos3x + 1/4sin4x
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-cos3x/3 + sin4x/4
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Maths Lecturer

-cos3x/3+sin4x/4
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-cos3x/3 + sin4x/4 + C.
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-cos3x/3 + sin4x/4+a; where 'a' is constant.
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Experienced Online Maths and Science Tutor with 10+ Years of Experience in Private Tutoring

Integration of since and cos x are - cos x and sin x respectively. Thus the answer is -1/3(cos 3x)+1/4(sin4x). Otherwise -1/12(4cos3x-3sin4x).
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Assistant Professor of Mathematics in Sharda University

-1/3cos3x+1/4sin4x
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As derivative of sinx + C is cosx so integral of cosx is sinx + c, where C is an arbitrary constant. We know integration is the inverse process of differentiation so integral of the given function is -1/3.cos3x + 1/4sin4x + c.
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Maths Expert

-(cos3x)/3 + (sin4x)/4 + C.
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Here is the complete solution to your problem.
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