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Asked by Swati Last Modified
Answer 
Spandan Maikap
Concepts involved :
1) specific gravity = density of liquid / density of water
2) boyancy force = volume immersed *density of liquid (ρ)* g( accn due to gravity)
3) weight of the object = total volume *density (σ)*g
Now since 1/6 th of the volume is above liquid surface 5/6 th is below it therefore by force balancing ( the upward boyancy force and downward gravity )
in case of water 5/6*V*ρ*g = V*σ*g ----(1)
in case of the other liquid λ*V*ρ'*g=V*σ*g ----(2)
Therefore from 1 and 2
λ*ρ' =5/6*ρ
λ*1.2=5/6*1
λ=25/36
Therefore the fraction of thw volume outside the surface of water = 9/36
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