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derivation of v2/r=ac

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B.tech

Below sheets has elaborate details of centripetal acceleration:
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Tutor

Hope it helps
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Mathematician

one need to identify dependent and independent variables before derivaive
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Circular motion at constant speed, v leads to ac = v2/r It may surprise you to learn that when a mass moves around a circle of radius r at constant speed, v, it is still accelearting because its DIRECTION is changing. This change in direction leads to a change in velocity because velocity is a vector!...
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Circular motion at constant speed, v leads to ac = v2/r It may surprise you to learn that when a mass moves around a circle of radius r at constant speed, v, it is still accelearting because its DIRECTION is changing. This change in direction leads to a change in velocity because velocity is a vector! When velocity changes, there is always an acceleration given by, ~aav = ~vf ? ~vi ?t (1) By using similar triangles it is possible to show that (see page 199 of text and/or go to lecture), ?v v= ?s r(2) so that ~ac = v r ?s ?t = v2r(3) where ac is the magnitude of the centripetal acceleration. Its direction is toward the center of the circle. This acceleration must be provided by a force, which in the case of a mass on a string is provided by the tension in the string. If this force is removed, the mass goes in a straight line. In the case of a car going around a corner, the force is produced by the tires on the road read less
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Tutor

It can be obtained if one knows about the terms involved in centripetal accelaration
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Tutor

Before derivation of it first we should know about centripetal force and terms like speed velocity ......
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Tutor

You can better refer s.l. arora for explanations.
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Software Engineer

You better have asked Google
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GST, Accounts & Computer Course

You better have asked Google
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