UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕

Take Class 12 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Book a Free Demo

Class 12 Tuition > Fill in the blanks by suitable conversion of units (a)...
✕

Search in

Fill in the blanks by suitable conversion of units (a) 1 kg m2 s-2 = �. g cm2 s-2 (b) 1 m =���� ly (c) 3.0 m s-2 = �. km h-2 (d) G = 6.67 x 10-11 N m2 (kg)-2 = �. (cm)3 s-2 g-1

Asked by Last Modified  

24 Answers

Follow 21
Answer

Please enter your answer

Tutor

Q(a)10^7 Q(b)1.06*10^-16 Q(c)10.8 Q(d)6.67*10^-8
Comments
Dislike Bookmark

JEE Main Maths, Physics With 12 years exp.

(a) 10^7 (b)1.06×10^-16 (C)10.8 (d)6.67×10^-8
Comments
Dislike Bookmark

Tutor

(a) 1 kg = 103 g1 m2 = 104 cm21 kg m2 s–2 = 1 kg × 1 m2 × 1 s–2=103 g × 104 cm2 × 1 s–2 = 107 g cm2 s–21 kg m2s–2= 107 g cm2 s–2 (b) Distance = Speed × TimeSpeed of light = 3 × 108 m/sTime = 1 year = 365 days = 365 × 24 hours...
read more
(a) 1 kg = 103g1 m2= 104cm21 kg m2s–2= 1 kg × 1 m2× 1 s–2=103g × 104cm2× 1 s–2= 107g cm2s–21 kg m2s–2=107g cm2s–2 (b)Distance = Speed × TimeSpeed of light = 3 × 108m/sTime = 1 year = 365 days = 365 × 24 hours = 365 × 24 × 60 × 60 secPutting these values in above formula we get1 light year distance = (3 × 108m/s) × (365 × 24 × 60 × 60 s) = 9.46 × 1015m9.46 × 1015m = 1 lySo that 1 m = 1/ 9.46 × 1015ly =1.06 × 10–16ly (c) 1 hour = 3600 sec so that 1 sec = 1/3600 hour1 km = 1000 m so that 1 m = 1/1000 km3.0 m s–2= 3.0 (1/1000 km)( 1/3600 hour)-2= 3.0 × 10–3km × ((1/3600)-2h–2)= 3.0 × 10–3km × (3600)2h–2= 3.88 × 104km h–23.0 m s–2=3.88 × 104km h–2(d)Given,G= 6.67 × 10–11N m2kg–2We know that1 N = 1 kg m s–21 kg = 103g1 m = 100 cm = 102cmPutting above values, we get6.67 × 10–11N m2kg–2= 6.67 × 10–11× (1 kg m s–2) (1 m2) (1Kg–2)Solve and cancel out the units, we get⇒ 6.67 × 10–11× (1 kg–1× 1 m3× 1 s–2)Putting above values to convert kg to g and m to cm⇒ 6.67 × 10–11× (103g)-1× (102cm)3× (1 s–2)⇒ 6.67 × 10–11× 10-3g-1× 106cm3× (1 s–2)⇒ 6.67 × 10–8cm3s–2g–1G= 6.67 × 10–11N m2kg–2 =6.67 × 10–8cm3s–2g–1 read less
Comments
Dislike Bookmark

Question (a) 10^7 Question (b)1.06×10^-16 Question (c)10.8 Question (d)6.67×10^-8
Comments
Dislike Bookmark

(a) 10^7 (b)1.06×10^-16 (C)10.8 (d)6.67×10^-8
Comments
Dislike Bookmark

(a) 10^7 (b)1.06×10^-16 (C)10.8 (d)6.67×10^-8
Comments
Dislike Bookmark

B. TECH.

Q(a)10^7 Q(b)1.06*10^-16 Q(c)10.8 Q(d)6.67*10^-8
Comments
Dislike Bookmark

Excellent track record tutor

Q(a)10^7 Q(b)1.06*10^-16 Q(c)10.8 Q(d)6.67*10^-8
Comments
Dislike Bookmark

Tutor

(a)10^7 (b)1.06*10^-16 (c)10.8 (d)6.67*10^-8
Comments
Dislike Bookmark

Tutor with teaching experience of 15+ years..

(a) 10^7 (b)1.06×10^-16 (C)10.8 (d)6.67×10^-8
Comments
Dislike Bookmark

View 22 more Answers

Related Questions

Why is it so dofficult to have my question answered?
Can you please post your question clearly. I have answered your previous question, I didn't get reply for it.
Esther
“At constant pressure the volume of a gas is proportional to the absolute temperature.” It is called __________. ((General Gas Law, Boyle’s Law, Charle’s Law, None of these)
charles law
Narendra Kumar
A crystal diode is used for rectification of __________. (AC current, DC current, Electromagnetic waves, None of the above)
Alternating Current
Narendra Kumar
0 0
7
To increase the accuracy in a potentiometer circuit __________ should be used. (A wire of a small length, A wire of a large length, A non uniform wire)
By increasing the length of the wire
Narendra Kumar
Find the equation of the line which is equidistant from parallel lines 9x + 6y - 7 = 0 and 3x + 2y + 6 = 0.
Re-writing the equation of lines in the form y=mx+c where m is the slope and c is the y-intercept. LINE (1) 9x + 6y = 7 taking 9x term to RHS, dividing by 6 on both sides and then after simplifying...
Kumar Upendra Akshay

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Sample Problem On Quadratic Equation.
If the roots of the equation a(b-c) x^2+b(c-a)x+c(a-b)=0 are equal then prove that 1/a + 1/c = 2 /b Solution : Since roots of the equation are equal, value of discrinant is zero. Which give...

Tapas Kumar Maity

0 0
0
Keep writing a habbit
Whenever you start study take some notes of it , make points describing that topic and start using highlighter so next you can revise the main points on the go.
L

Leena S.

0 0
0
Problem on limits
Let's solve a problem on limits Find limit: x→0 (1 - cos2x ) /(x²) On direct substitution we get 1 - 1/0 = 0/0 which is in indeterminate form Let's substitute (1 - cos 2x ) = 2 sin²...

B.Sudhakar

3 0
0
Dissolution Of Partnership Firm - Questions
CHAPTER: 5 Q.1 Distinguish between dissolution of partnership and dissolution of partnership firm on the basis of continuation of business. Q.2 Why is Realisation Account prepared on dissolution of partnership...

Mahesh Kumar

1 0
0
How to understand Mensuration - Simplified.
One of the chapters in X standard Maths that students feel tough is the chapter of Mensuration. However, its one of the most easiest chapter to score as well!! How? Lets take an interesting formula on...

Hari Kurup

0 0
0

Recommended Articles

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Meet Swati, a Hindi Tutor from Bangalore

Swati is a renowned Hindi tutor with 7 years of experience in teaching. She conducts classes for various students ranging from class 6- class 12 and also BA students. Having pursued her education at Madras University where she did her Masters in Hindi, Swati knows her way around students. She believes that each student...

Read full article >

Meet Radhe Shyam Burman, an MBA Tutor from...

Radhe Shyam is a highly skilled accounts and finance trainer with 8 years of experience in teaching. Accounting is challenging for many students and that’s where Radhe Shyam’s expertise comes into play. He helps his students not only in understanding the subject but also advises them on how to overcome the fear of accounts...

Read full article >

Find Class 12 Tuition near you
Class 12 Tuition in Delhi
Class 12 Tuition in Bangalore
Class 12 Tuition in Chennai
Class 12 Tuition in Hyderabad
Class 12 Tuition in Kolkata
Class 12 Tuition in Mumbai
Class 12 Tuition in Pune
Class 12 Tuition in Lucknow
Class 12 Tuition in Gurgaon
Class 12 Tuition in Noida
Online Tuition Class 12

Looking for Class 12 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 12 Tuition Classes?

The best tutors for Class 12 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 12 Tuition with the Best Tutors

The best Tutors for Class 12 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2025 All Rights Reserved