0Answer:
Method 1:
A = [(k + 1)/k ]^k
B = [(k/(k - 1)]^(k - 1)
Apply PMI now to get : A > B
Method 2:
Solution:
(1+ 1/n)^n = e ~ 2.78xx.. as n tends to infinity.
Now its an increasing function because just check for
A = (1 +1/2)^2 and B= (1 +1)^1 ==> A= 9/4= 2.25 and B=2. So clearly A>B here.
So, as the function is increasing so, it will also satisfy for our given A and B. i.e., A>B here.
f(x)= (1 + 1/x)^x is alwz an increasing function. and as it is increasing function so, if x> y then f(x) > f(y) alwz.
It also satisfies from here.
