There are 4 men and 3 women sitting on the round table. In how many ways can they be seated such that 1 women come in between 2 men?

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Path founder

168
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Tutor

First fix the men in circular arrangement, which can be done in 3! (n-1!). Now there are 4 places between the men and three women are to be seated between the men. That can be done in 4P3 ways. Again you get 144 arrangements.
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(4-1)!×4C3×3!
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4! * 4P3 ways
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Tutor

72
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4! * 3! M _ M _ M _M
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Teacher

M=Male F=Female 4M and 3F 4+3=7 MFMFMFM =7 7!/3!x4! 7x6x5x4x3x2x1 _______________ (3x2x1)(4x3x2x1) =35
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Experienced Mathematics com ECE Educator

answer is 7! / (4! * 3!) = 7*6*5 / 1*2*3 = 35
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Physics Subject Expert

7!/3!*4! = 35
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Assistant Professor

35
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Evaluate: 8! - 3!?
8!=8*7*6*5*4*3*2*1 3!=3*2*1 8!-3!=8*7*6*5*4*3*2*1-3*2*1 =3*2*1(8*7*6*5*4-1) =6(6720-1) =6(6719) = 40314 Ok all the best.
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Deepa
Evaluate: 5! - 2!?
=(5*4*3*2*1)-(2*1) =(120)-(2) =118
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Neelima
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Using all the letters of the word "FRIDAY", how many different words can be formed?
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