Integration of sin4x+Cos4x?

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((-Cos4x)+Sin4x)/4+C
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Expeienced Maths and Science Tutor

-cox4x/4+sin4x/4
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"Investment in knowledge pays the best return."

4(cos4x - sin4x)
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-cos4x+sin4x/4+c
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Maths Tutor, Maths Faculty at Jr. College

-cos4x/4 + sin4x/4
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1/4 *(Sin4x - Cos4x) + c, where c is a contant
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Math Magician

-cos4x/4+sinx/4
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Hello I think in tenth class integration is not in course . But the answer ur are asking from me is that -cos4x/4+sin4x/4
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((-cos(4x))/4)+ ((sin(4x))/4)
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Physics Lecturer

If we let t=4x dt=4 dx implies dx=(dt/4) Therefore the equation becomes integration(sin t+ cos t) dt./4 We know int of sin t is -cos t ,and int of cos t is sin t (if you don't, mug it up. Very very imp) Hence the answer is (-cos t + sin t)/4 +constant. but t = 4x Hence answer is (sin...
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If we let t=4x dt=4 dx implies dx=(dt/4) Therefore the equation becomes integration(sin t+ cos t) dt./4 We know int of sin t is -cos t ,and int of cos t is sin t (if you don't, mug it up. Very very imp) Hence the answer is (-cos t + sin t)/4 +constant. but t = 4x Hence answer is (sin 4x- cos 4x)/4 + constant read less
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