In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately.

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Let the no. of marks obtained in Maths = x & no. of marks obtained in Science = 28-x It is given that (x+3)(28-x-4) = 180 (x+3)(24-x)=180 24x-x2+72-3x=180 x2-21x+108 = 0 x2-12x-9x+108=0 x(x-12)-9(x-12)=0 (x-9)(x-12)=0 therefore answer is x =9 or 12 For x = 9 Marks obtained in Maths = 9 Marks...
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Let the no. of marks obtained in Maths = x & no. of marks obtained in Science = 28-x It is given that (x+3)(28-x-4) = 180 (x+3)(24-x)=180 24x-x2+72-3x=180 x2-21x+108 = 0 x2-12x-9x+108=0 x(x-12)-9(x-12)=0 (x-9)(x-12)=0 therefore answer is x =9 or 12 For x = 9 Marks obtained in Maths = 9 Marks obtained in Science = 19 We can check for (9+3)*(19-4) = 180 For x =12 Marks obtained in Maths = 12 Marks obtained in Science = 16 So we can check (12+3)*(16-4) = 180 Hence, both cases are possible solutions read less
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Maths=18 marks & Science=10 marks
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Teacher

18 and 10
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Eco, Maths and Stats Tutor

m+s=28 (m+3x)(s-4)=180 Forming the quadratic equation in s and solving we get s=16(->m=12) or s=19(->m=9).
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18 and 10 respectively
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X=18 and y=10
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