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Two different dice are tossed together. Find the probability: (i) That the numbers on either die is even. (ii) That the sum of numbers appearing on the two dice is 5.

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Even numbers can occur in the following ways : Dice I Dice II
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Teacher

Even numbers can occur in the following 9 ways when two dices are cast Dice I 2 4 6 Dice II 2 or 4 or 6 2 or 4 or 6 2 or 4 or 6 All possible outcomes is 6 x 5 = 36. So the desired probability is 9/36 = 1/4 Sum...
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Even numbers can occur in the following 9 ways when two dices are cast Dice I 2 4 6 Dice II 2 or 4 or 6 2 or 4 or 6 2 or 4 or 6 All possible outcomes is 6 x 5 = 36. So the desired probability is 9/36 = 1/4 Sum of 5 can occur in any of these 4 ways Dice I 1 2 3 Dice II 4 or 1 3 2 Hence the required probability is 4/36 = 1/9 read less
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18/36 4/36
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18/36 4/36
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18/36 4/36
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18/36 4/36
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i. 9/36. ii. 4/36.
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Tutor

i. (3+3+3) = 9 no of possibilities total =6*6=36. p (i) =9/36 ii. (1+4)=5 (2+3)=5 (3+2)=5 (4+1)=5 Total possibilities = 4 p(ii)=4/36.
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Tutor

Total number of possibilities are 36 Probability of numbers on either die is even is 24/36=2/3 2) probability of the sum of numbers appearing on the two dices is 4/36=1/9
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