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Class 10 > If cosec |=3x and cot |=3/x. then find the value of...
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If cosec |=3x and cot |=3/x. then find the value of (x2-1/x2)

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CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

=1/9 use formula cosec² x -cot² x =1
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Tutor

cosecβ = = 3X and cotβ = 3/X , to find value ( X2 - 1/X2 ) . we know , cosec2β = cot2β +1 putting value , (3X )2 = ( 3/X )2 +1 , OR 9X2 = 9 /X2 + 1 , OR 9X2 – 9/X2 = 1, OR 9( X2 - 1/X2 ) = 1, SO (X2 – 1/X2 ) = 1/9
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cosecβ = = 3X and cotβ = 3/X , to find value ( X2- 1/X2) . we know , cosec2β = cot2β +1 putting value , (3X )2= ( 3/X)2+1 , OR 9X2= 9 /X2 + 1 , OR 9X2– 9/X2= 1, OR 9( X2- 1/X2) = 1, SO (X2– 1/X2) = 1/9 read less
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Chemistry Teacher

Cosec^2A = 1 + cot^2 A (3x)^2 - 1/(3x)^2 = 1 9{(x)^2 - 1/(x)^2 = 1/(9) ans
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x=cosec/3
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Coaching Institute

1/9
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Science Teacher

the answer is given in the following attachment
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Eco, Maths and Stats Tutor

cosec(^2)l=9x(^2). cot(^2)l=9/(x^2). Use cosec(^2)l-cot(^2)l=1. Then x^2-1/x^2=1/9
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Trainer

Cosec^2x -Cot^2x = 1 (From Formula) From Question, (3x)^2-(3/x)^2=1 3*(x+1/x)*3*(x-1/x)=1 Therefore,(x+1/x) (x-1/x)=1/9 x^2-1/x^2=1/9
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cosec^2 I - cot^ l = 1 (3x)^2- (3/x)^2=1 9x^2 - 9/x^2 =1 9(x^2- 1/x^2)=1 x^2-1/x^2 =1/9
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Mathematics Tutor

From right angle triangle we get (3/x)^2+1=(3x)^2 9x^2-9/(x^2)=1 x^2-1/x^2=1/9
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