If cosec |=3x and cot |=3/x. then find the value of (x2-1/x2)

Asked by Last Modified  

20 Answers

Learn Mathematics +1

Follow 21
Answer

Please enter your answer

Salman Ahmad Siddiqui

CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

=1/9 use formula cosec² x -cot² x =1
Comments
Dislike Bookmark

Tutor

cosecβ = = 3X and cotβ = 3/X , to find value ( X2 - 1/X2 ) . we know , cosec2β = cot2β +1 putting value , (3X )2 = ( 3/X )2 +1 , OR 9X2 = 9 /X2 + 1 , OR 9X2 – 9/X2 = 1, OR 9( X2 - 1/X2 ) = 1, SO (X2 – 1/X2 ) = 1/9
read more
cosecβ = = 3X and cotβ = 3/X , to find value ( X2- 1/X2) . we know , cosec2β = cot2β +1 putting value , (3X )2= ( 3/X)2+1 , OR 9X2= 9 /X2 + 1 , OR 9X2– 9/X2= 1, OR 9( X2- 1/X2) = 1, SO (X2– 1/X2) = 1/9 read less
Comments
Dislike Bookmark

Chemistry Teacher

Cosec^2A = 1 + cot^2 A (3x)^2 - 1/(3x)^2 = 1 9{(x)^2 - 1/(x)^2 = 1/(9) ans
Comments
Dislike Bookmark
x=cosec/3
Comments
Dislike Bookmark

Coaching Institute

1/9
Comments
Dislike Bookmark

Science Teacher

the answer is given in the following attachment
Comments
Dislike Bookmark

Eco, Maths and Stats Tutor

cosec(^2)l=9x(^2). cot(^2)l=9/(x^2). Use cosec(^2)l-cot(^2)l=1. Then x^2-1/x^2=1/9
Comments
Dislike Bookmark

Trainer

Cosec^2x -Cot^2x = 1 (From Formula) From Question, (3x)^2-(3/x)^2=1 3*(x+1/x)*3*(x-1/x)=1 Therefore,(x+1/x) (x-1/x)=1/9 x^2-1/x^2=1/9
Comments
Dislike Bookmark

cosec^2 I - cot^ l = 1 (3x)^2- (3/x)^2=1 9x^2 - 9/x^2 =1 9(x^2- 1/x^2)=1 x^2-1/x^2 =1/9
Comments
Dislike Bookmark

Mathematics Tutor

From right angle triangle we get (3/x)^2+1=(3x)^2 9x^2-9/(x^2)=1 x^2-1/x^2=1/9
Comments
Dislike Bookmark

View 18 more Answers

Related Questions

how i can be a tutor?

 
First and most important thing is command on your subject. Alway put first thing first. use your imagination to plan lecture and guess the doubts and problem that student may have.
Shivam
Which is best book for class 10th CBSE maths preparation?
See,there are hell amount of books in maths. First and foremost go for all the questions in CBSE book as well as exemplar, pay attention to all questions being taught in class and further you may purchase any book if neccessity arises.
Saukat
0 0
6
What is the correct timetable for a class 10 student?
Everyone has one particular time that they are habituated to study and grasp more at that particular time.Always choose your toughest subject at that particular time to study either it is maths,science,...
Pavan
0 0
6
Find the mean proportion of 25, 64?
Mean proportion = square root of (25*64) = 40 Ans.
Balaji
1 0
8
If the areas of two similar triangles are in ratio 25 : 64, write the ratio of their corresponding sides.
5:8.
Priya

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

CHAPTER-10 CIRCLES NCERT SOLUTIONS
Exercise: 10.1 How many tangents can a circle have? Answer A circle can have infinite tangents. Fill in the blanks : (i) A tangent to a circle intersects it in ..................

Rahul S

0 0
0

Saurav

0 0
0
Class-10 L-8 Introduction to Trigonometry Ex-8.2 Q2 (ii)

Ashish Bhatia

0 0
0
Class-10 L-1 Real Numbers Ex-1.1 Q2 (ii)

Ashish Bhatia

0 0
0
Question: Triangle ABC is a right angled triangle , right angled at B. The pink circle , of radius 4 cm touches the three sides of the triangle and the blue circle , with radius 1 cm , touches the pink...

Sujoy Das

2 0
0

Recommended Articles

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Quest Academy - Institute of the month

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Find Class 10 Tuition near you
Class 10 Tuition in Delhi
Class 10 Tuition in Bangalore
Class 10 Tuition in Hyderabad
Class 10 Tuition in Kolkata
Class 10 Tuition in Chennai
Class 10 Tuition in Mumbai
Class 10 Tuition in Pune
Class 10 Tuition in Noida
Class 10 Tuition in Lucknow
Class 10 Tuition in Gurgaon
Online Tuition Class 10

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you