If cosec |=3x and cot |=3/x. then find the value of (x2-1/x2)

Asked by Last Modified  

20 Answers

Learn Mathematics +1

Follow 21
Answer

Please enter your answer

CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

=1/9 use formula cosec² x -cot² x =1
Comments

Tutor

cosecβ = = 3X and cotβ = 3/X , to find value ( X2 - 1/X2 ) . we know , cosec2β = cot2β +1 putting value , (3X )2 = ( 3/X )2 +1 , OR 9X2 = 9 /X2 + 1 , OR 9X2 – 9/X2 = 1, OR 9( X2 - 1/X2 ) = 1, SO (X2 – 1/X2 ) = 1/9
read more
cosecβ = = 3X and cotβ = 3/X , to find value ( X2- 1/X2) . we know , cosec2β = cot2β +1 putting value , (3X )2= ( 3/X)2+1 , OR 9X2= 9 /X2 + 1 , OR 9X2– 9/X2= 1, OR 9( X2- 1/X2) = 1, SO (X2– 1/X2) = 1/9 read less
Comments

Chemistry Teacher

Cosec^2A = 1 + cot^2 A (3x)^2 - 1/(3x)^2 = 1 9{(x)^2 - 1/(x)^2 = 1/(9) ans
Comments

x=cosec/3
Comments

Coaching Institute

1/9
Comments

Science Teacher

the answer is given in the following attachment
Comments

Eco, Maths and Stats Tutor

cosec(^2)l=9x(^2). cot(^2)l=9/(x^2). Use cosec(^2)l-cot(^2)l=1. Then x^2-1/x^2=1/9
Comments

Trainer

Cosec^2x -Cot^2x = 1 (From Formula) From Question, (3x)^2-(3/x)^2=1 3*(x+1/x)*3*(x-1/x)=1 Therefore,(x+1/x) (x-1/x)=1/9 x^2-1/x^2=1/9
Comments

cosec^2 I - cot^ l = 1 (3x)^2- (3/x)^2=1 9x^2 - 9/x^2 =1 9(x^2- 1/x^2)=1 x^2-1/x^2 =1/9
Comments

Mathematics Tutor

From right angle triangle we get (3/x)^2+1=(3x)^2 9x^2-9/(x^2)=1 x^2-1/x^2=1/9
Comments

View 18 more Answers

Related Questions

Why is there linear algebra but not nonlinear algebra?
The term "nonlinear algebra" is not as well-defined as the term "linear algebra." This is because there is no single agreed-upon definition of what "nonlinear algebra" is. Some mathematicians use the term...
Kadar
0 0
7
In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately.
Let the marks of mathematics be x Than marks of science be 28-x now according to question (x+3), (28-x-4) The product of new marks will be 180 So, (x+3) (28-x-4)=180 24x-x^2+72-3x=180 x^2-21x+108=0 x^2-12x-9x+108=0 x(x-12)-9(x-12)=0 (x-9)(x-12)=0 (x-9)=0...
Sanjay
0 0
7

What is the fees for peivate tuition for 10th State board and CBSE board for Mathematics?

Depending upon the area in which you are going to give classes but according to me it should be at least â?¹6000-7000 per month
Shyam Cholera
In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately.
Let the no. of marks obtained in Maths = x & no. of marks obtained in Science = 28-x It is given that (x+3)(28-x-4) = 180 (x+3)(24-x)=180 24x-x2+72-3x=180 x2-21x+108 = 0 x2-12x-9x+108=0 x(x-12)-9(x-12)=0 (x-9)(x-12)=0 therefore...
Suresh
0 0
6
The lengths of the diagonals of a rhombus are 30 cm and 40 cm. Find the side of the rhombus.
diagonals of a rhombus are perpendicular bisector so we can find side of rhombus with pythagoras theorem. H^2 = P^2 + B^2 Side^2 = 15^2 + 20^2 Side^2 = 225 + 400 Side^2 = 625 Side = 25
Satish
0 0
5

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons




Number System
Number System: There are two majaor division in the Number System i.e. 1. Real Number System 2. Complex Number System Real Number System: (SYMBOL Is "R") It is a set that contains following sets...
J

Janaki Saravanan S

0 0
0

Recommended Articles

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you