A bag contains 6 nails and 10 nuts. half of the nails and half of the nuts are rusted. if one item is chosen at random then find the probability that it is rusted and is a nail.

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SINCE HALF OF THE NAILS ARE RUSTED, THERE ARE 6X(1/2)=3 RUSTED NAILS. TOTAL NUMBER OF ITEMS IS 10+6=16. SO PROBABILITY=3/16
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Since half of the nails are rusted, there are 3 rusted nails. total number of items= 16. so probability is 3/16.
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3/16
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Probability of choosing a nail is 6/16, where No. of nails = 6 and Total number of nails and nuts = 6+10= 16. Now that we have chosen nails, half of them are rusted. So probability is (6/16)*(1/2) = 3/16.
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P = 3/16
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Probability that item is rusted P(A) = 8/16 , Probability that item is nail, P(B) = 6/16, Probability (rusted and nail) = P(A intersection B)
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6/16 * 1/2
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1/2 and 3/16
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