If a gas has density 3 l /gm .What would be its molar mass?

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Wilfred Thomas

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First of all, the unit of density is gm/l not l/gm (mass/volume). We must use ideal gas equation. PV= nRT, so that n/v = P/RT. Multiplying the left hand side by molar mass M is the density in gm/l. So that, (n/v)xM= (P/RT)xM = density(d). So M = dRT/P. So the temperature and pressure must be provided...
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Density depends on both pressure and temperature. Hence without mentioning pressure and temperature we can't solve. Required formula: Density= (pressure ×molar mass)/(universal gas constant ×temperutre ink). On doing this problem be careful of unit.
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A philanthropist, keen observer and a chemical engineering graduate from NIT Surat

is the question correct? density=g/l and not l/g. let's take d=3 g/l T=25 deg C (298K) using standard if not given P= 1 bar R= 0.08314 l.bar/K.mol According to the Ideal gas law: PV=nRT thus, P/RT=n/V now, n=no. of moles= wt. of compound(gas in this case)/molar mass of compound hence,...
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is the question correct? density=g/l and not l/g. let's take d=3 g/l T=25 deg C (298K) using standard if not given P= 1 bar R= 0.08314 l.bar/K.mol According to the Ideal gas law: PV=nRT thus, P/RT=n/V now, n=no. of moles= wt. of compound(gas in this case)/molar mass of compound hence, n=m/M where m=wt. of compound thus, P/RT= m/(V.M) or P/RT= (m/V)/M now, d=density=m/V thus, P/RT=d/M or M= d/ (P/RT) or M= dRT/P M= 3 (g/l).0.08314(l.bar/(K.mol)). 298 K/1bar M= 74.3272 g/mol read less
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molar mass= 2×vapour density = 2×3 =6
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Math Educator for Std.11th ,12th , Engineering Entrance and Degree Level with 11+ Years Experience

density = mass / volume so its unit can be gm / l not l / gm. first write accurate problem then ask
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Mathematician

First you should correct the unit of density then apply PM=dRT and find ur ans
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Please mention the element/compound name of the gas?
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Something doesn't look correct in the question as unit of density is not l/gm, Since d=mass/volume, so numerator must have a unit of mass and same for denominator.
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