The taxi fare in a city is as follows: For the first kilometre, the fare is Rs. 8 and for thesubsequent distance it is Rs. 5 per km. Taking the distance covered as x km and totalfare as `Rs. y, write a linear equation for this information, and draw its graph.

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Total distance covered = x km Fare for 1st kilometre = Rs 8 Fare for the rest of the distance = Rs (x − 1) 5 Total fare = Rs y = 8 + 5x − 5 y = 5x + 3 5x − y + 3 = 0 It can be observed that point (0, 3) and satisfies the above equation. Therefore, these are the solutions of this equation. x 0 ...
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Total distance covered =xkm Fare for 1stkilometre = Rs 8 Fare for the rest of the distance = Rs (x− 1) 5 Total fare = Rs [8 + (x− 1) 5] y= 8 + 5x− 5 y= 5x+ 3 5x−y+ 3 = 0 It can be observed that point (0, 3) andsatisfies the above equation. Therefore, these are the solutions of this equation. x 0 y 3 0 The graph of this equation is represented as follows: It can be noticed that variablexandyare representing the distance covered and the fare paid for that distance respectively. These quantities may not be negative. Hence, only those values ofxandy lying in the 1stquadrant will be considered. read less
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