Find the amount of water displaced by a solid spherical ball of diameter(i) 28 cm(ii) 0.21 m

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(i) Radius (r) of ball = Volume of ball = Therefore, the volume of the sphere is cm3. (ii)Radius (r) of ball = = 0.105 m Volume of ball = Therefore, the volume of the sphere is 0.004851 m3.
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(i) Radius (r) of ball = Volume of ball = Therefore, the volume of the sphere iscm3. (ii)Radius (r) of ball == 0.105 m Volume of ball = Therefore, the volume of the sphere is 0.004851 m3. read less
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Volume of a sphere = 4/3 π r3 (where 'r' is the radius of the sphere) Using this formula, we get,(i) When diameter is 28 cm, then radius(r) is 14 cm. So, volume = (4/3)x (22/7)x (14x14x14) = 11498.67 cc.(ii) When diameter is 0.21 m or 21cm, radius(r) is 10.5 cm. So, Volume = (4/3) x (22/7) x (10.5x10.5x10.5)=...
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Volume of a sphere = 4/3 π r3 (where 'r' is the radius of the sphere) Using this formula, we get,(i) When diameter is 28 cm, then radius(r) is 14 cm. So, volume = (4/3)x (22/7)x (14x14x14) = 11498.67 cc.(ii) When diameter is 0.21 m or 21cm, radius(r) is 10.5 cm. So, Volume = (4/3) x (22/7) x (10.5x10.5x10.5)= 4851 cc.Now, we know according to Archimedes principle that when a body is completely or partially immersed in a fluid, it displaces the volume of fluid which is equal to the volume of immersed part of the body.So, assuming the spheres were entirely immersed in water, we can say that the amount of water displaced by the spheres would be (i) 11498.67 cc. i.e. 11498.67 gms of water. ( Density of water= 1gm/cc)(ii) 4851 cc i.e. 4851 gms of water. read less
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