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An umbrella is made by stitching 10 triangular pieces of cloth of two different colours (see Figure), each piece measuring 20 cm, 50 cm and 50 cm. How much cloth of eachcolour is required for the umbrella?

CBSE/Class 9/Mathematics/Unit 5-Mensuration/Heron's formula/NCERT Solutions/Exercise 12.2

For each triangular piece, Semi-perimeter, By Heron’s formula, Area of triangle Since there are 5 triangular pieces made of two different coloured cloths, Area of each cloth required read more

For each triangular piece,

Semi-perimeter,

By Heron’s formula,

Area of triangle

Since there are 5 triangular pieces made of two different coloured cloths,

Area of each cloth required

Area of each triangular cloth = √60 ( 60 - 50 ) ( 60 - 50 ) ( 60 - 20 ) = √60 × 10 × 10 × 40 = √ 2 × 2 × 3 × 5 × 10 × 10 × 2 × 2 × 2 × 5 = 2 × 2 × 10 × 5 √3 × 2 = 200√6cm². Cloth... read more

Area of each triangular cloth

= √60 ( 60 - 50 ) ( 60 - 50 ) ( 60 - 20 )

= √60 × 10 × 10 × 40 = √ 2 × 2 × 3 × 5 × 10 × 10 × 2 × 2 × 2 × 5 = 2 × 2 × 10 × 5 √3 × 2

= 200√6cm².

Cloth required for each colour = 200√6 × 5 = 1000√6cm².

Mca Certified Home/Online Tutor With 12 Years Experience.

1000

Mathematics home tutor having 6 years of teaching experience

1000√6 cm²

IITian with 20 Years of teaching exp. and IIM Calcutta MBA

1000x cloth of each colour is required for the umbrella. Use Haron's formula.

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