Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the distance between AB and CD is 6 cm, find the radius of the circle.

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Draw OM ⊥ AB and ON ⊥ CD. Join OB and OD. (Perpendicular from the centre bisects the chord) Let ON be x. Therefore, OM will be 6− x. In ΔMOB, In ΔNOD, We have OB = OD (Radii of the same circle) Therefore, from equation (1) and (2), From equation (2), Therefore, the...
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Draw OM ⊥ AB and ON ⊥ CD. Join OB and OD. (Perpendicular from the centre bisects the chord) Let ON bex. Therefore, OM will be 6−x. In ΔMOB, In ΔNOD, We have OB = OD (Radii of the same circle) Therefore, from equation (1) and (2), From equation (2), Therefore, the radius of the circle iscm. read less
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