A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate (i) the maximum height to which it rises. (ii)the total time it takes to return to the surface of the earth.

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(i) 122.5 m (ii) 10 s According to the equation of motion under gravity: v2 − u2 = 2 gs Where, u = Initial velocity of the ball v = Final velocity of the ball s = Height achieved by the ball g = Acceleration due to gravity At maximum height, final velocity of the ball is zero, i.e., v = 0 u = 49...
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(i) 122.5 m(ii) 10 s According to the equation of motion under gravity: v2−u2= 2 gs Where, u= Initial velocity of the ball v= Final velocity of the ball s= Height achieved by the ball g= Acceleration due to gravity Atmaximum height, final velocity of the ball is zero, i.e.,v= 0 u= 49 m/s During upward motion, g= − 9.8 m s−2 Lethbe the maximum height attained by the ball. Hence, Lettbe the time taken by the ball to reach the height 122.5 m, then according to the equation of motion: v=u+ gt We get, But, Time of ascent = Time of descent Therefore, total time taken by the ball to return = 5 + 5 = 10 s read less
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