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Simplify and solve the linear equation 

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15(y − 4) − 2(y − 9) + 5(y + 6) = 0 ⇒ 15y − 60 − 2y + 18 + 5y + 30 = 0 (Opening the brackets) ⇒ 18y − 12 = 0 ⇒ 18y = 12 ⇒
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15(y − 4) − 2(y − 9) + 5(y + 6) = 0

⇒ 15y − 60 − 2y + 18 + 5y + 30 = 0 (Opening the brackets)

⇒ 18y − 12 = 0

⇒ 18y = 12

 

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Prepared for Future

15(y-4)-2(y-9)+5(y+6)=0 (15y-60)-(2y-18)+(5y+30)=0 15y-60-2y+18+5y+30=0 (15y-2y+5y)=(60-18-30) 18y=12 y=12/18 y=2/3
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Engineering graduate from NIT Calicut, Rank holder (#47) in State Entrance Examination.

15(y-4)-2(y-9)+5(y+6)=0 15y-15*4-2y+2*9+5y+30=0 on rearranging terms, 15y-2y+5y-60+18+30=0 18y-12=0 18y=12 y=12/18 y=2/3
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