Convert the following into basic units: (i) 28.7 pm (ii) 15.15 µs (iii) 25365 mg

Asked by Last Modified  

Follow 2
Answer

Please enter your answer

28.7×10 power 9 m 15.15×10 power -3 sec 0.025365kg
Comments

Home Tutor

(i) 1 pm = 10-12 m28.7 pm = 28.7×10-12 m = 2.87×10-11 m(ii) 1 pm = 10-12 m∴15.15 pm = 15.15×10-12 m = 1.515 ×10-11 m(iii) 1 mg = 10-3 g25365 mg = 2.5365×104×10-3 gNow,1 g = 10-3 kg2.5365×10 g = 2.5365×10×10-3 kg∴25365 mg = 2.5365×10-2...
read more
(i) 1 pm =10-12m28.7 pm = 28.7×10-12m= 2.87×10-11m(ii)1 pm =10-12m∴15.15 pm = 15.15×10-12m= 1.515 ×10-11m(iii)1 mg =10-3g25365 mg = 2.5365×104×10-3gNow,1 g =10-3kg2.5365×10 g = 2.5365×10×10-3kg∴25365 mg = 2.5365×10-2kg read less
Comments

Related Questions

Is it important to join coaching in class 11?
• If you are an average student (getting 55-75% marks) or below average you need help from tuition !! • if you have chosen different streams other than SCIENCE like Arts , Commerce and you...
Gulfam
0 0
9
The radius of Na+ cation is less than that of Na atom. Give reason.
No. Of shell of Na+ ion is less than the no. Of shell Na atom
A.mohamed
0 0
9
Which is the best chemistry branch for Msc in chemistry?
Material chemistry has a great scope these days. It gives you varied experience and field exposure.
User
0 0
9
How shall I prepare for IIT without joining any coaching institute? I am in class 11.
focus on basic concepts of subjects, prepare timetable for study and follow this. does not spent too much time on study but start learning on calm mind, do some physical activity also.
Priya
0 0
7

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons


Mole concept
P

Pooja S.

0 0
0

Basics of Mole concept
What is Mole? If we talk of quantity a Dozen then it is 12 Pair= 2 Dozen and pair both are quantities without having unit,similiarly Mole is quantity which is equal to 6.023x1023. Now imagine hypothetically...

Phenols Notes on NEET & Boards
Phenols are organic compounds characterized by a hydroxyl group (-OH) directly attached to a benzene ring. For NEET preparation, focus on their structure, acidity, reactions, and nomenclature, particularly...

convert the following compounds to benzene? (i)Ethyne. (ii)Ethene. (iii)Hexane.
QUESTION How would you convert the following compounds to benzene? (i)Ethyne. (ii)Ethene. (iii)Hexane. ANSWER

Recommended Articles

E-learning is not just about delivering lessons online. It has a much broader scope that goes beyond manual paper or PowerPoint Presentations. To understand the reach of E-learning and how the whole process works in developing the Educational system, we will discuss a few points here. Let us find out how this new learning...

Read full article >

Quality education does not only help children to get a successful career and life, but it also hugely contributes to society. The formal education of every child starts from school. Although there are numerous schools, parents find it challenging to choose the right one that would fit their child. It is difficult for them...

Read full article >

While schools provide formal education to the children, the home is where they start learning about things informally. Parents think that schools will take the initiative to educate their children. Well, this is partially true, as parents also play an essential role in bringing up their child. For the development of particular...

Read full article >

With the current trend of the world going digital, electronic renaissance is a new movement that is welcomed by the new generation as it helps makes the lives of millions of people easier and convenient. Along with this rapidly changing movement and gaining popularity of Internet, e-Learning is a new tool that emerging...

Read full article >

Looking for Class 11 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you