A bullet fired at an angle of 30° with the horizontal hits the ground 3.0 km away. By adjusting its angle of projection, can one hope to hit a target 5.0 km away? Assume the muzzle speed to the fixed, and neglect air resistance.

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D Mukherjee

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The formula for Range = v^2/g x sin 2A Given 3000 = v^2/g x sin 60 Hence v^2/g = 3000/sin 60 = 6000/1.732 = 3464.2 The Range will be maximum when the angle pf firing is 45 degree Range = v^2/g x sin 90 = 3464.2 x 1 = 3464.2 m So the bulet will not hit a target 5000 m away.
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