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Calcium carbonate reacts with aqueous HCl according to the reaction CaC03 (s) + 2HCl (aq) ———->CaCl2(aq) +C02(g) +H2O(l). What mass of CaC03 is required to react completely with 25 mL of 0.75 M HCl?

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9.3831 g
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