In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal, how much is the net work done by the system in the latter case? (Take 1 cal = 4.19 J).

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The work done (W) on the system while the gas changes from state A to state B is 22.3 J. This is an adiabatic process. Hence, change in heat is zero. ∴ ΔQ = 0 ΔW = –22.3 J (Since the work is done on the system) From the first law of thermodynamics, we have: ΔQ = ΔU...
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The work done (W) on the system while the gas changes from state A to state B is 22.3 J. This is an adiabatic process. Hence, change in heat is zero. ∴ ΔQ = 0 ΔW = –22.3 J (Since the work is done on the system) From the first law of thermodynamics, we have: ΔQ = ΔU + ΔW Where, ΔU = Change in the internal energy of the gas ∴ ΔU = ΔQ – ΔW = – (– 22.3 J) ΔU = + 22.3 J When the gas goes from state A to state B via a process, the net heat absorbed by the system is: ΔQ = 9.35 cal = 9.35 × 4.19 = 39.1765 J Heat absorbed, ΔQ = ΔU + ΔQ ∴ΔW = ΔQ – ΔU = 39.1765 – 22.3 = 16.8765 J Therefore, 16.88 J of work is done by the system. read less
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