In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.

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Diameter of the circle = 40 cm ∴Radius (r) of the circle = Let AB be a chord (length = 20 cm) of the circle. In ΔOAB, OA = OB = Radius of circle = 20 cm Also, AB = 20 cm Thus, ΔOAB is an equilateral triangle. ∴θ = 60° = We know that in a circle of radius r unit,...
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Diameter of the circle = 40 cm ∴Radius (r) of the circle = Let AB be a chord (length = 20 cm) of the circle. In ΔOAB, OA = OB = Radius of circle = 20 cm Also, AB = 20 cm Thus, ΔOAB is an equilateral triangle. ∴θ = 60° = We know that in a circle of radius r unit, if an arc of length l unit subtends an angle θ radian at the centre, then. Thus, the length of the minor arc of the chord is. read less
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