Find the principal and general solutions of the equation

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Engineering graduate from NIT Calicut, Rank holder (#47) in State Entrance Examination.

tanx=-1/√3 tan Π/6=1/√3 tan(Π-x)=-tanx=-1/√3 tan(Π-Π/6)=tan(5Π/6)=-1/√3 tan(2Π-x)=-tanx=-1/√3 tan(2Π-Π/6)=tan(11Π/6)=-1/√3 principal solutions are 5Π/6 and 11Π/6 tanx=tan5Π/6 x=nΠ+5Π/6, n∈Z is the general solution
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tanx=-1/√3 tanΠ/6=1/√3 tan(Π-x)=-tanx=-1/√3 tan(Π-Π/6)=tan(5Π/6)=-1/√3 tan(2Π-x)=-tanx=-1/√3 tan(2Π-Π/6)=tan(11Π/6)=-1/√3 principal solutions are 5Π/6 and 11Π/6 tanx=tan5Π/6 x=nΠ+5Π/6, n∈Z is the general solution read less
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Therefore, the principal solutions are x = and. Therefore, the general solution is
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Therefore, the principal solutions are x = and. Therefore, the general solution is read less
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