Calculate the enthalpy change for the process CCl4(g) → C(g) + 4 Cl(g) and calculate bond enthalpy of C – Cl in CCl4(g). ∆vapH(CCl4) = 30.5 kJ mol–1. ∆f H (CCl4) = –135.5 kJ mol–1. ∆aH (C) = 715.0 kJ mol–1 , where ∆aHis enthalpy of atomisation ∆aH (Cl2) = 242 kJ mol–1

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