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Navendu Shekhar Engineering Entrance trainer in Delhi

Navendu Shekhar

Mathematics faculty for iitjee and boards

Patel Nagar, Delhi, India - 110008.

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Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Hello,
I teach according to the students understanding level. Every student is unique and have their unique level of understanding. I first observe their way of catching concepts and then I try to clear their doubts. My subject is mathematics and physics and I have taught more than 1000 students from different parts of the world ( online + offline).

You will find me like a tutor you always wanted to have. So contact me if you really want to see the interesting and funny parts of mathematics and physics. Best of luck for your studies and remember pure and unbiased education is your right and you must have it.

Languages Spoken

Hindi

English

Education

Indraprastha university 2016

Bachelor of Technology (B.Tech.)

Address

Unnamed Road, Block I, West Patel Nagar, Patel Nagar

Patel Nagar, Delhi, India - 110008

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Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

3

Reviews

No Reviews yet!

Answers by Navendu Shekhar (3)

Answered 1 day ago Learn CBSE/Class 10/Mathematics/UNIT IV: Geometry/Triangles/NCERT Solutions/Exercise 6.5

Tick the correct answer and justify : In , AB = cm, AC = 12 cm and BC = 6 cm. The angle B is : (A) (B) (C) (D) ...more
Tick the correct answer and justify :

In , AB = cm, AC = 12 cm and BC = 6 cm. The angle B is :

(A)  (B)  (C) (D)

It is a right angled triangle and hence B is 90degrees.
Answers 4 Comments
Dislike Bookmark

Answered 1 day ago Learn CBSE/Class 10/Mathematics

How do I apply for class 10 tutoring?

 

You can create your profile on various Edtech applications.
Answers 10 Comments
Dislike Bookmark

Answered 1 day ago Learn CBSE/Class 10/Mathematics

x+1=?

X and x-1 are the perpendicular and base with x+1 as its hypotenuse. After using pythagoras theorem you get sum of squares of perpendicular and base is equal to the square of its hypotenuse. Therefore, x+1=5
Answers 10 Comments
Dislike Bookmark

Contact

Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

3

No Reviews yet!

Answers by Navendu Shekhar (3)

Answered 1 day ago Learn CBSE/Class 10/Mathematics/UNIT IV: Geometry/Triangles/NCERT Solutions/Exercise 6.5

Tick the correct answer and justify : In , AB = cm, AC = 12 cm and BC = 6 cm. The angle B is : (A) (B) (C) (D) ...more
Tick the correct answer and justify :

In , AB = cm, AC = 12 cm and BC = 6 cm. The angle B is :

(A)  (B)  (C) (D)

It is a right angled triangle and hence B is 90degrees.
Answers 4 Comments
Dislike Bookmark

Answered 1 day ago Learn CBSE/Class 10/Mathematics

How do I apply for class 10 tutoring?

 

You can create your profile on various Edtech applications.
Answers 10 Comments
Dislike Bookmark

Answered 1 day ago Learn CBSE/Class 10/Mathematics

x+1=?

X and x-1 are the perpendicular and base with x+1 as its hypotenuse. After using pythagoras theorem you get sum of squares of perpendicular and base is equal to the square of its hypotenuse. Therefore, x+1=5
Answers 10 Comments
Dislike Bookmark

Contact

Navendu Shekhar describes himself as Mathematics faculty for iitjee and boards. He conducts classes in Class IX-X Tuition, Class XI-XII Tuition (PUC) and Engineering Entrance Coaching. Navendu is located in Patel Nagar, Delhi. Navendu takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 3 years of teaching experience . Navendu has completed Bachelor of Technology (B.Tech.) from Indraprastha university in 2016. He is well versed in Hindi and English.

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