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Class 10 > Evaluate the identity: ?
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Evaluate the identity: [cube of (99)]?

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(a-b)^3 = a^3-3a^2b+3ab^2-b^3. (99)^3 = (100 -1)^3.
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(a+b)^3=a3 + 3a^2b + 3ab^2 + b^3, thus, 99^3=(100-1)^3. Taking 100 as a, and 1 as b, we can use the formula (a+b)^3 given above to expand and get the answer.
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