(1/a), (3 – a)/3a, (3 – 2a)/3a,… (a ≠ 0)

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The given sequence is an arithmetic progression (AP) with a common difference. To find this common difference, let's subtract each term from the next one:
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The given sequence is an arithmetic progression (AP) with a common difference. To find this common difference, let's subtract each term from the next one: read less
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Related Questions

How to find whether a sequence of numbers are in Arithmetic Progression or not?
Verify if the difference between the consecutive terms is the same.
Avinash
What is sum of an infinite geometric progression(GP)
S =a/1-r' where a is first term and r is common difference and less than 1
Avinash
Is there any relation between AM, GM, HM in Progressions?
Yes relationship is present and also equation is also present
Avinash
Find the number of terms of the A.P: 7, 13, 19, ...., 205?
The first term, t1=a = 7. The common difference, b=13 - 7=6. Last term or the nth term, tn=a + (n-1)b = 205. So, we have, 7 + (n - 1)6 = 205 --> (n - 1) = (205 - 7)/6 = 33 --> n = 34. Answer: Number of terms is 34.
Swati
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If Sn denotes the sum of the first n terms in an Arithmetic Progression and S1: S4 = 1: 10. Then the ratio of first term to third term is _______ ?
It will be 1:7
Avinash

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