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What is sum of an infinite geometric progression(GP)

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CBSE/Class 10/Mathematics Progressions Tuition/Class IX-X Tuition

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it is a/(1-r) provided |r|<1 otherwise series can't converge.


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a/(1-r).......where a is the first term, r is the common ratio(ratio between any two consecutive numbers)

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S=a/1-r, if r(common ratio)1

Sn =a/1-r ,where a- first term and r- is common ratio

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Sn =a/(1-r),where a is first term and r is common ratio.


Sum of an infinite GP equals a/1 - r where a is the first term and r is the common ration S=a/1-r, if r(common ratio)1

The sum of infinite G.P is a/(1-r) where a is the first term and r is the common ratio


Sum of an infinite GP equals a/1 - r where a is the first term and r is the common ration.

a/(1-r) ; a= first term r=common ratio

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