The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field.

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Let the length of the shorter side be x metres. The length of the diagonal= 60+x metres The length of the longer side =30+x metres Applying Pythagoras theorem, Diagonal²=longer side²+shorter side² (60+x) ²= (30+x) ² + x² 3600+120x+x²=900+60x+x²+x² 2700+60x-x²=0 2700+90x-30x-x²=0 90(30+x)-x(30+x)...
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Let the length of the shorter side be x metres. The length of the diagonal= 60+x metres The length of the longer side =30+x metres Applying Pythagoras theorem, Diagonal²=longer side²+shorter side² (60+x)²= (30+x)² + x² 3600+120x+x²=900+60x+x²+x² 2700+60x-x²=0 2700+90x-30x-x²=0 90(30+x)-x(30+x) =0 X=90, Shorter side is 90m, longer side is 90+30=120m read less
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Sides are 90 m and 120m
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90 &120 meters
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Let shorter side be x Diagonal = x+60 Longer side =x+30 By applying Pythagoras theorem Shorter side = 90m Longer side =120m
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Smaller Side = 90m Larger Side = 120m Diagonal = 150m
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The smaller side is 90. The longer side is 120.
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The longest side of the triangles i.e. the hypotenuse.So, by Pythagoras Theorem,(Diagonal)² = (Smaller Side)² + (Longer Side)²(x + 60)² = (x)² + (x + 30)²x² + 120x + 3600 = x² + x² + 60x + 900x² + 60x - 120x + 900 - 3600 = 0x² - 60x - 2700 = 0x²...
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The longest side of the triangles i.e. the hypotenuse.So, by Pythagoras Theorem,(Diagonal)² = (Smaller Side)² + (Longer Side)²(x + 60)² = (x)² + (x + 30)²x² + 120x + 3600 = x² + x² + 60x + 900x² + 60x - 120x + 900 - 3600 = 0x² - 60x - 2700 = 0x² - 90x + 30x - 2700 = 0x(x - 90) + 30(x - 90) = 0(x - 90) (x + 30) = 0x = 90 because x = -30 as length cannot be possible.So the length of the shorter side is 90 meters and the length of the longer side is 90 + 30 = 120 meters. read less
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length of small side = 90m length of longer side = 120m diagonal= 150m
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Longer side 120m and shorter side 90m.
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Length 120 m, Breadth 90 m
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