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How I can add for a student

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By advertising through newspaper pamphlet register on tutor sites
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Commerce/COST/TAX/FINANCE/ACCOUNTS TUTOR

Go to the option ,then attendance,find add student and then add student you wanted to add
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Certified Onlie Tutor

Open urban pro account,in that you can see 2 windows-enquiry and students. Open student and click on + symbol to add a student.
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Related Questions

The perimeter of one face of a wooden cube is 20 cm. Find its weight if 1 cm3 of wood weighs 8.25 g.
Let a be the side of cube,Perimeter of a wooden cube=20cm=4aWe know, Perimeter of a cube = 4a Therefore, 4a = 20cm a = 5cm=
Kanak
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If the radius of the base of a cone is doubled keeping the height same. What is the ratio of the volume of the larger cone to the smaller cone?
When we take height=h and radios of base=r then volume of cone=?r^2*h/3 if radios of the base is doubled then R=2r and height=h so, volume is =?(2r)^2*h/3 therefore, ratio of the volume of latter cone...
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Is polynomial y4 + 4y2 + 5 have zeroes or not?
The polynomial y4 + 4y2 + 5 has no zero(s) because the roots are not real.
Veerendra
How can I score good percentage in my class 10 CBSE boards exam?
Do regular study and stay focused. Read and revised theory and numerical at regular intervals. Work hard on the weak subject and if required take tuition of that subject. NCERT books reading is very important...
Sharmistha
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How do I get over 95% in the ICSE class 10 board exams?
U can get 95% marks if u work hard and study regularly 8to 10hours daily.u have also first go through the text book throghly and the do practice from different samples papers and 10years of previous years...
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Volume of the Cone
VOLUME OF THE CONE If, r=radis of the cone h= perpendicular height Then, 1)The volume of the cone =( 1/3 )πr2h Ex- If,r=14 cm, h=15cm, then 1)The volume of the cone =( 1/3 )πr2h ...


INTRODUCTION TO TRIGONOMETRY
Any triangle has three sides and three angles. But Is there any relation between the sides and angles of a triangle? Trigonometry aims to answer this question. Before entering into its terms, let's...

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