Priyanka R.

Indian Institute Of Technology, Chennai, India - 600036

Indian Institute Of Technology, Chennai, India- 600036.

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I got an AIR of 1520 in IITJEE, hence have a strong hold in mathematics and science. I am currently pursuing a dual degree in mechanical engineering from IIT Madras. I studied in ICSE board till tenth and passed with a percentage of 97. English is one of my strengths. I have taught mathematics for high school students, training for competitive examinations for a summer. Students studying in KV, in the IIT campus will find the location very convenient.

Kannada

Hindi

English

Indian Institute of Technology, Madras Pursuing

Bachelor of Technology (B.Tech.)

Indian Institute Of Technology, Chennai, India - 600036

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Class I-V Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class I-V Tuition

1

Fees

₹ 175 per hour

Board

CBSE, ICSE, State

CBSE Subjects taught

English, Science, Social Science

ICSE Subjects taught

English, Mathematics, Science

Taught in School or College

Yes

State Syllabus Subjects taught

Science, EVS, Mathematics, English, Computer Science, Social Science

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5.0 out of 5.0 1 review

5.0/51

D

16 Feb, 2018

Divanshu Kumar attended Class 9 Tuition

"Punctual and hardworking. She always was on time and gave enough time to my student. She is passionate about teaching. "

Have you attended any class with Priyanka? Write a Review

Answered on 09/02/2018 CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

The two numbers can be any unknown variables. We will take x and y. Reversing 165, we get 561 which means that adding them will give me 561. Subtracting the two I will get 3. Conveting them to equations we get x+y =561 x-y = 3 Adding the two equations we get 2x=564 x=282 Substituting the value of... ...more

The two numbers can be any unknown variables. We will take x and y.

Reversing 165, we get 561 which means that adding them will give me 561.

Subtracting the two I will get 3. Conveting them to equations we get

x+y =561

x-y = 3

Adding the two equations we get

2x=564

x=282

Substituting the value of x in (x-y=3)

282-y=3

Therefoe, y=279

Like 0

Answers 4 Comments PriyankaDirections

x Class I-V Tuition 4.7

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class I-V Tuition

1

Fees

₹ 175 per hour

Board

CBSE, ICSE, State

CBSE Subjects taught

English, Science, Social Science

ICSE Subjects taught

English, Mathematics, Science

Taught in School or College

Yes

State Syllabus Subjects taught

Science, EVS, Mathematics, English, Computer Science, Social Science

Class 6 Tuition 4.7

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

CBSE, State, ICSE

CBSE Subjects taught

Computers, Mathematics, Hindi, English, Social Science, Science

ICSE Subjects taught

English, Mathematics, Biology, Physics, Chemistry, Computer Science

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, EVS, Hindi, Science, Social science, English

Class 7 Tuition 4.7

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

CBSE, State, ICSE

CBSE Subjects taught

Computers, Mathematics, Hindi, English, Social Science, Science

ICSE Subjects taught

English, Mathematics, Biology, Physics, Chemistry, Computer Science

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, EVS, Hindi, Science, Social science, English

Class 8 Tuition 4.7

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

CBSE, State, ICSE

CBSE Subjects taught

Computers, Mathematics, Hindi, English, Social Science, Science

ICSE Subjects taught

English, Mathematics, Biology, Physics, Chemistry, Computer Science

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, EVS, Hindi, Science, Social science, English

Class 9 Tuition 4.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

CBSE, ICSE, State

CBSE Subjects taught

English, Science, Mathematics

ICSE Subjects taught

English Literature, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

English, Science, Mathematics

Class 10 Tuition 4.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

CBSE, ICSE, State

CBSE Subjects taught

English, Science, Mathematics

ICSE Subjects taught

English Literature, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

English, Science, Mathematics

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

5.0 out of 5.0 1 review

D

16 Feb, 2018

Divanshu Kumar attended Class 9 Tuition

"Punctual and hardworking. She always was on time and gave enough time to my student. She is passionate about teaching. "

Have you attended any class with Priyanka? Write a Review

Answered on 09/02/2018 CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

The two numbers can be any unknown variables. We will take x and y. Reversing 165, we get 561 which means that adding them will give me 561. Subtracting the two I will get 3. Conveting them to equations we get x+y =561 x-y = 3 Adding the two equations we get 2x=564 x=282 Substituting the value of... ...more

The two numbers can be any unknown variables. We will take x and y.

Reversing 165, we get 561 which means that adding them will give me 561.

Subtracting the two I will get 3. Conveting them to equations we get

x+y =561

x-y = 3

Adding the two equations we get

2x=564

x=282

Substituting the value of x in (x-y=3)

282-y=3

Therefoe, y=279

Like 0

Answers 4 Comments Share this Profile

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