Sanjay Pushpakar photo

Sanjay Pushpakar

Mathematics is all what i do !

Sector-45, Chandigarh, India- 160047.

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Overview

I am a B.Tech graduate from IIT Roorkee and have been teaching Mathematics to students for more than 4 years now.

I started teaching engineering students for their Campus Placements and CAT examination in 2011. An year later in 2012, i started teaching school students for their board examinations and competitive examinations like IIT JEE and state CET.

I am a hardcore mathematics lover. I teach and learn Mathematics. Three of the topmost things i learn about teaching are the way it makes even the teacher to learn, the way their is a two sided interaction between students and teacher, and the happiness it brings when we make someone learn and share our learning what we teachers already have.

My teaching strengths lie in in depth knowledge of my subject, precise delivery exactly what student requires for good results and my own involvement in making sure a student learns.

As part of my achievements, i cleared IIT JEE with an all india rank of 681, AIEEE with a state rank of 32 and AIAEE with a state rank of 1.

Demo Class

No

Languages Spoken

Punjabi, Hindi, English

Education

Bachelor of Technology (B.Tech.) from IIT Roorkee in 2010.

Address

Sector-45, Chandigarh, India- 160047.

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BA Tuition

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Answers by Sanjay Pushpakar (4)

". Atom consists of __________. (Electrons, Protons, Neutrons, All of these)" in   Tuition/Class XI-XII Tuition (PUC)

All of these

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"A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?" in   Exam Coaching/Quantitative Aptitude

10/21

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"If increasing 20 by P percentage gives the same result as decreasing 60 by P percentage,What is P percentage of 70?" in   Exam Coaching/Quantitative Aptitude

35

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"If increasing 20 by P percentage gives the same result as decreasing 60 by P percentage,What is P percentage of 70?" in   Exam Coaching/Quantitative Aptitude

Increasing 20 by P percent, we will get 20(1+(P/100)), and decreasing 60 by P percent, we will get 60(1-(P/100)). Equating the two expressions, we get P = 50 percent. 50 percent of 70 will be 70 X (50/100) = 35

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Sanjay Pushpakar address

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BA Tuition
BCA Tuition
BCom Tuition
BSc Tuition
CET Coaching classes
Class IX-X Tuition
Class XI-XII Tuition (PUC)
Non-Verbal Aptitude Coaching
Quantitative Aptitude Coaching
Verbal Aptitude Coaching

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No Reviews yet! Be the first one to Review

". Atom consists of __________. (Electrons, Protons, Neutrons, All of these)" in   Tuition/Class XI-XII Tuition (PUC)

All of these

0
|
0

"A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?" in   Exam Coaching/Quantitative Aptitude

10/21

0
|
0

"If increasing 20 by P percentage gives the same result as decreasing 60 by P percentage,What is P percentage of 70?" in   Exam Coaching/Quantitative Aptitude

35

0
|
0

"If increasing 20 by P percentage gives the same result as decreasing 60 by P percentage,What is P percentage of 70?" in   Exam Coaching/Quantitative Aptitude

Increasing 20 by P percent, we will get 20(1+(P/100)), and decreasing 60 by P percent, we will get 60(1-(P/100)). Equating the two expressions, we get P = 50 percent. 50 percent of 70 will be 70 X (50/100) = 35

0
|
0

Sanjay Pushpakar describes himself as Mathematics is all what i do !. He conducts classes in BA Tuition, BCA Tuition and BCom Tuition. Sanjay is located in Sector-45, Chandigarh. Sanjay takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 4 years of teaching experience . Sanjay has completed Bachelor of Technology (B.Tech.) from IIT Roorkee in 2010. HeĀ is well versed in Punjabi, Hindi and English.

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