IIM-Bangalore to Conduct CAT 2016 (News)
The CAT (Common Admission Test), one of the most popular management entrance tests in India, will be conducted by IIM-B in 2016. Considered as the gateway to prestigious IIMs and top B-Schools, every year lakh of students across India take up the test. CAT 2015 was conducted on 29th November, and around the same time the exam is likely to be conducted this year. A preliminary discussion will be conducted in the 1st week of June, 2016. Read more…
Exam patterns of CAT 2016
The Common Admission Test had undergone a number of changes in the last few years. However, there are no new changes in CAT exam patterns this year. Like 2015, CAT will consist of 3 Sections – Quantitative Aptitude (QA), Data Interpretation & Logical Reasoning (DILR) and Verbal and Reading Comprehension (VRC). A total of 100 questions would be asked – QA (34 questions), VRC (34 questions) and DILR (32 questions). Read more…
Tips to crack CAT 2016
Preparing for CAT 2016? Get excellent tips, strategies, and expert advice on how to crack the exam. CAT is one of the most coveted management entrance exams in India and the competition is increasing year after year. To give an edge to your CAT preparation, follow these effective tips. Read more…
CAT Coaching Lessons
The first n natural numbers, 1 to n, have to be arranged in a row from left to right. The n numbers are arranged such that there are an odd number of numbers between any two even numbers as well as between any two odd numbers. If the number of ways in which this can be done is 72, then find the value of n?
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Bhargava Vadlamani | 6 days ago
Correction:- It is (n-1)/2 ! * (N+1)/2 ! So if n is 7 then answer is 144 If n is 5 then answer is 12.
Vikram Prabhakaran | 6 days ago
It needs to be visualized first that there can be only 1 odd number between any two even numbers and vice versa because if you place 3 odd numbers between 2 even numbers then some pair of even numbers will not have any odd numbers between them lets assume a set of numbers 1, 2, 3, 4, 5, 6 2, 1 ,3 ,5 ,4 ,6 not satisfying the condition thus we have only 2 of types possibility that satisfies the given condition: 1 2 3 4 5 6 2 1 4 3 6 5 the two types of possibility happened because the number of odd and number of even numbers are same but for a set of odd numbers there will be only one type of possibility i.e. starting with odd numbers. e.g.:- 2 3 4 5 1 not satisfying the condition 1 2 3 4 5 Now coming to the question. Lets suppose, n is even and thus n = 2t+2 (where t is an integar with t>0) thus t+1 even numbers and t+1 odd numbers 2*(t+1)! (t+1)! = 72 (t+1)! = 6 t = 2 n = 6. Lets suppose n is odd and thus n = 2t+1 (where t is an integar with t>0) thus t even numbers and t+1 odd numbers (2t+1)! (t)! = 72 for t=1 rhs =6 for t=2 rhs =240 thus the above equation will not be satisfied for any value of t. Hence, n = 6
What is the eligibility criteria for appearing CAT exam?
Velmurugan Sivappraghassan | 4 days ago
Any graduate degree in engineering & in science subjects.
Shyam went from Delhi to Simla via Chandigarh by car. The distance from Delhi to Chandigarh is 3/4 times the distance from Chandigarh to Simla. The average speed from Delhi to Chandigarh was half as much again as that from Chandigarh to Simla. If the average speed for the entire journey was 49 kmph, what was the average speed from Chandigarh to Simla?
Kiran Rindani | 6 days ago
Delhi ---------------- Chandigarh ---------------- shimla Distance 3x/4 km x km Speed 3y/2 kmph y kmph Time (3x/4)/(3y/2) hrs = 3x/2y hrs x/y hrs average speed = (total distance)/(total time) 49 = (x + 3x/4)/(x/2y + x/y) = (7x/4)/(3x/2y) = 7y/6 49 = 7y/6 --- y = 42 kmph --- (ANS)
The winning relay team in a high school sports competition clocked 4-8 minutes for a distance of 13.2 km. Its runners A, B, C and D maintained speeds of 15 kmph, 16 kmph, 17 kmph and 18 kmph respectively. What is the ratio of the time taken by B to that taken by D?
Sourav Sir's Classes | 01 Dec
c) Since it is a relay race, all the runners ran the same distance. Hence for a same distance, (ratio of times) = 1/(ratio of speeds). Hence ratio of times taken by B t& D = 18 : 16 = 9 : 8.
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