Is there any reason to use bitwise operations such as 'n<< 1' rather than just 'n * 2'? Isn't the compiler in charge of such optimizations?

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Avinash Patel

Yes, its better to use bitwise operations. But this also depends on the programmers context of use because with modern compilers on modern architectures, there is generally no difference in performance.
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C++ Pro . I talk to robots in C++. Data Structures. IT Professional Trainer

Well, you have already answered your question. Since you know n<<1 is already an optimized version of n*2. So basically if you use this in your code, there wont be any further conversion from n*2 to n<<1. And yes, Compiler may do such optimization but if you already using it in your code...
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Well, you have already answered your question. Since you know n<<1 is already an optimized version of n*2. So basically if you use this in your code, there wont be any further conversion from n*2 to n<<1. And yes, Compiler may do such optimization but if you already using it in your code before hand, your program will run faster. read less
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