How do I print "I love programming" as many times the user want in C++ Programming without using the loop (while, do/while and for)?

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Abhishek Jain

Cin >> counter Use this counter in for loop.
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C++ Tutor; Make it easy.

Using recursion; #include<iostream> void printNTimes(int nTimes){ if(nTimes <= 0) return; std::cout<<"I love programming\n"; printNTimes(--nTimes);} int main(){ int n = 0; std::cin>>n; printNTimes(n);}
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Using recursion; #include<iostream> void printNTimes(int nTimes){ if(nTimes <= 0) return; std::cout<<"I love programming\n"; printNTimes(--nTimes);} int main(){ int n = 0; std::cin>>n; printNTimes(n);} read less
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Electrical Engineer from IIT Kanpur ,By profession Software Engineer and Teacher by passion

1) Use Recursion. (as given in the other answer). But in Recursion there is one drawback, if the number is enormous, your process stack may overflow, and your program may terminate.2) The other way (trick) is to - Design a class. - In the constructor of the class (which should not take any argument),...
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1) Use Recursion. (as given in the other answer). But in Recursion there is one drawback, if the number is enormous, your process stack may overflow, and your program may terminate.2) The other way (trick) is to - Design a class. - In the constructor of the class (which should not take any argument), in the constructor body, print the line "I love programming". After that, in your primary function, declare an array or vector of this class object of size equal to what the user has entered.Don't forget to check the negative or zero aspect of the input number. It should be a positive integer. read less
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