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The probability that in a year of 22nd century chosen at random, there will be 53 Sundays is ?

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It is a problem of conditional probability. A century have 100 years in which 25 years are leap years(because leap year occurs after every 4 years) and 100-25=75 non-leap years. For leap year, The probability of a leap year in a century is 25/100 = 1/4 The probability of getting 53rd sunday in a leap...
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It is a problem of conditional probability. A century have 100 years in which 25 years are leap years(because leap year occurs after every 4 years) and 100-25=75 non-leap years.

For leap year,

The probability of a leap year in a century is 25/100 = 1/4

The probability of getting 53rd sunday in a leap year is 2/7 (A leap year has 52 weeks and 2 days. So, 53rd sunday can occur 2 times out of 7 possibilities, ((sunday,monday), (monday,tuesday), (tuesday,wednesday), (wednesday,thursday), (thursday, friday), (friday,saturday), (saturday,sunday)))

So, the probability of getting 53 sundays in a leap year is (1/4) * (2/7) = 2/28

For non leap year,

The probability of getting a non leap year in a century is 75/100 = 3/4

The probability of getting 53rd sunday in a non leap year is 1/7 (A non leap year has 52 weeks and 1 day. So, sunday can occur 1 time out of 7 possibilities (sunday, monday, tuesday, wednesday, thursday, friday, saturday))

The probability of getting 53 sundays in a non leap year is (3/4) * (1/7) =3/28

Thus, the probability of getting 53 sundays in a century is (2/28) + (3/28) = (5/28)

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