UrbanPro

Take BTech Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Search in

Can anyone help me with the below programs: A) which returns orger summary as a list with 2- tuples. Each tuple consists of the order number and the product of the price per items and the quantity. OUTPUT: [ ('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97) ]. 10 INR should be increased in the product if the value of the order is smaller than 100.00 INR. OUTPUT: [ ('34587',163.8),('98762',284.0),(77226',108.85),('88112',84.97) ]

Asked by Last Modified  

24 Answers

+3 Python Python Anaconda Python Advanced

Follow 7
Answer

Please enter your answer

Build Yourself For The Future

Can't solve because product price is a part of the tuple. Since LIST IS MUTABLE so we can change its elements. We can change the whole tuple because it is an element of the list. As WKT TUPLE IS IMMUTABLE so we can't change its elements.
Comments

Senior Software Engineer/Java Full Stack Developer.

public class DemoApplication { public static void main(String args) { //SpringApplication.run(DemoApplication.class, args); List<Order> list=new ArrayList(); list.add(new Order("34587", 163.8)); list.add(new Order("98762", 284.0)); list.add(new Order("77226", 98.85)); list.add(new Order("88112",...
read more
public class DemoApplication { public static void main(String[] args) { //SpringApplication.run(DemoApplication.class, args); List<Order> list=new ArrayList(); list.add(new Order("34587", 163.8)); list.add(new Order("98762", 284.0)); list.add(new Order("77226", 98.85)); list.add(new Order("88112", 74.97)); System.out.println("Before Processing List orders :: "+list); int index=-1; for(Order order: list) { index++; if(order.getPrice()<100) { order.setPrice(order.getPrice()+10); list.set(index, order); } } System.out.println("After processing List orders :: "+list); } } class Order{ private String orderNo; private double price; public Order(String orderNo, double price) { super(); this.orderNo = orderNo; this.price = price; } public void setOrderNo(String orderNo){ this.orderNo=orderNo; } public String getOrderNo(){ return orderNo; } public void setPrice(double price){ this.price=price; } public double getPrice(){ return price; } @Override public String toString() { return "Order [orderNo=" + orderNo + ", price=" + price + "]"; } } read less
Comments

IT Professional with 2 years of experience

Hello Anurag, As per your question, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of...
read more
Hello Anurag, As per your question, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list. Program: 1) With regular for-loop: # You might use list(input()) to read list from user input. inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)] outputList = [] for _tuple in inputList: if (_tuple[1] < 100): outputList.append((_tuple[0], _tuple[1]+10)) else: outputList.append((_tuple[0],_tuple[1])) print('Updated List:',outputList) PS: Since tuples are immutable (cannot change it's value further) in python, we used one more list instead of replacing the given input list itself. 2) With list-comprehension:- inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)] def getUpdatedList(inputList): return [(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList] outputList = getUpdatedList(inputTuple) print(outputList) Or simply, print([(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]) Feel free to ask me any further questions. Happy Coding!!! read less
Comments

IT Professional with 2 years of experience

Hello Anurag, As per your question, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of...
read more
Hello Anurag, As per your question, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list. Program: 1) With regular for-loop: # You might use list(input()) to read list from user input. inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)] outputList = [] for _tuple in inputList: if (_tuple[1] < 100): outputList.append((_tuple[0], _tuple[1]+10)) else: outputList.append((_tuple[0],_tuple[1])) print('Updated List:',outputList) PS: Since tuples are immutable (cannot change it's value further) in python, we used one more list instead of replacing the given input list itself. 2) With list-comprehension:- inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)] def getUpdatedList(inputList): return [(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList] outputList = getUpdatedList(inputTuple) print(outputList) Or simply, print([(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]) Feel free to ask me any further questions. Happy Coding!!! read less
Comments

IT Professional with 2 years of experience

Hello Anurag, As per your query, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a,...
read more
Hello Anurag, As per your query, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list. Program: 1) With regular for-loop: # You might use list(input()) to read list from user input. inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)] outputList = [] for _tuple in inputList: if (_tuple[1] < 100): outputList.append((_tuple[0], _tuple[1]+10)) else: outputList.append((_tuple[0],_tuple[1])) print('Updated List:',outputList) PS: Since tuples are immutable (cannot change it's value further) in python, we used one more list instead of replacing the given input list itself. 2) With list-comprehension:- inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)] def getUpdatedList(inputList): return [(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList] outputList = getUpdatedList(inputTuple) print(outputList) Or simply, print([(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]) Feel free to ask me any further questions. Happy Coding!!! read less
Comments

IT Professional with 2 years of experience

Hello Anurag, As per your query, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a,...
read more
Hello Anurag, As per your query, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list. Program: 1) With regular for-loop: # You might use list(input()) to read list from user input. inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)] outputList = [] for _tuple in inputList: if (_tuple[1] < 100): outputList.append((_tuple[0], _tuple[1]+10)) else: outputList.append((_tuple[0],_tuple[1])) print('Updated List:',outputList) PS: Since tuples are immutable (cannot change it's value further) in python, we used one more list instead of replacing the given input list itself. 2) With list-comprehension:- inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)] def getUpdatedList(inputList): return [(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList] outputList = getUpdatedList(inputTuple) print(outputList) Or simply, print([(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]) Feel free to ask me any further questions. Happy Coding!!! read less
Comments

Pyhton Djabgo Flask Trainer (7618030342)

Hi, Anurag, You can use List comprehension if the input list is lst then, lst = new_lst =
Comments

I am an entrepreneur and have more than 35 years of experience in the IT industry

Hello Anurag, Here is a simpler solution ... OUTPUT = oL, OUTPUTL = , oT = () for i in range(len(OUTPUT)): # convert the tuple to list oL.append(list(OUTPUT)) if oL < 100.00: # make the changes to the price oL += 10.00 # convert the list back to tuple ...
read more
Hello Anurag, Here is a simpler solution ... OUTPUT = [ ('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97) ] oL, OUTPUTL = [], [] oT = () for i in range(len(OUTPUT)): # convert the tuple to list oL.append(list(OUTPUT[i])) if oL[i][1] < 100.00: # make the changes to the price oL[i][1] += 10.00 # convert the list back to tuple oT = tuple(oL[i]) # append the tuple to the list OUTPUTL.append(oT) # overwrite the original OUTPUT OUTPUT = OUTPUTL print("OUTPUT", OUTPUT) read less
Comments

I am an entrepreneur and have more than 35 years of experience in the IT industry

OUTPUT = oL, OUTPUTL = , oT = ()for i in range(len(OUTPUT)): # convert the tuple to list oL.append(list(OUTPUT)) if oL < 100.00: # make the changes to the price oL += 10.00 # convert the list back to tuple oT = tuple(oL) # append the tuple to the list OUTPUTL.append(oT)#...
read more
OUTPUT = [ ('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97) ] oL, OUTPUTL = [], []oT = ()for i in range(len(OUTPUT)): # convert the tuple to list oL.append(list(OUTPUT[i])) if oL[i][1] < 100.00: # make the changes to the price oL[i][1] += 10.00 # convert the list back to tuple oT = tuple(oL[i]) # append the tuple to the list OUTPUTL.append(oT)# overwrite the original OUTPUTOUTPUT = OUTPUTLprint("OUTPUT", OUTPUT) read less
Comments

I have cracked IES exam,GATE,many PSU. And I would love to deliver the knowledge I have got.

Hi Anurag, Hope You are doing well with your coding, As per your requirement, # this is the input OUTPUT= # this is the output list in which your output will come ol= for i in OUTPUT: if i<100 : ol.append((i,i+10)) else: ol.append((i,i)) print(ol) Because Tuples are immutable,An...
read more
Hi Anurag, Hope You are doing well with your coding, As per your requirement, # this is the input OUTPUT= [ ('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97) ] # this is the output list in which your output will come ol=[] for i in OUTPUT: if i[1]<100 : ol.append((i[0],i[1]+10)) else: ol.append((i[0],i[1])) print(ol) Because Tuples are immutable,An Empty list has been taken to fill the required output. I hope this piece of code solves your problem.Actually it can be solved in other ways also. Regards Deepak read less
Comments

View 22 more Answers

Related Questions

Is coaching necessary for the CBSE class 12?
Actually for disciplined study you need proper guidance to carry forward your syllabus easily without any hurdles that may be when someone is sharing his or her knowledge with proper guidance and all...
Sriomprakash
0 0
5
I need help with my engineering mathematics syllabus
Its very easy math u can contact any tytor for one month
Shubham
Can I do an Mba after Btech in Biotechnology?
Yes you can do MBA after your B.Tech Completion and nothing can stop you from doing that.
Shiva
0 0
6

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Telomeres (Boon or Curse)!
It's undoubtedly a boon, but in some context (cancer), it has to be considered as a curse.Replication of DNA is one of the essential and eminent processes of the central dogma of life. This occurs in both...

Answer writing skills for the final examination
Dear Students,Answer writing for the final examination is explained clearly in the videos so please watch the video and also subscribe for the channel for more examination techniques.

Learning a new technology
Each and every day new technologies are getting introduced. Its quite clear that to be part of the fast moving professional world you should be upto date with the cutting edge technologies in the market....
S

Saurav Singh

1 0
0

What Is The Diffrence Between 1st Angle And 3rd Anglle Projections?
In first angle projection object lies between observer and projection plane and in third angle projection plane of projection lies between observer and object. A person with spects is example of 3rd angle projection :

Introductory Discussions On Complexity Analysis
What is Complexity Analysis of Algorithm? Complexity Analysis, simply put, is a technique through which you can judge about how good one particular algorithm is. Now the term “good” can mean...

Recommended Articles

According to a recent survey conducted by the NCAER (National Council of Advanced Economic Research), engineering is the most sought after course in India. Some engineering courses are offered as BE or Bachelor of Engineering while some as Bachelor in Technology or B.Tech. Since engineering is a professional course, the...

Read full article >

MBA, Medicine and engineering are the three main professional courses in India. Engineering is still one of the highly sorted after professional courses in the under graduate level, while MBA is favoured as a preferred post graduate course. To shine in these courses, one needs to work and study hard. Engineering as a...

Read full article >

Appearing for exams could be stressful for students. Even though they might have prepared well, they could suffer from anxiety, tension etc. These are not good for their health and mind. However, following a few exam preparation tips can save them from all these and help them to score good marks. Let’s find out all...

Read full article >

With the current trend of the world going digital, electronic renaissance is a new movement that is welcomed by the new generation as it helps makes the lives of millions of people easier and convenient. Along with this rapidly changing movement and gaining popularity of Internet, e-Learning is a new tool that emerging...

Read full article >

Looking for BTech Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for BTech Tuition Classes?

The best tutors for BTech Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take BTech Tuition with the Best Tutors

The best Tutors for BTech Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more